document.write( "Question 1192522: (1 point) It is estimated that approximately 8.37% Americans are afflicted with diabetes. Suppose that a certain diagnostic evaluation for diabetes will correctly diagnose 98% of all adults over 40 with diabetes as having the disease and incorrectly diagnoses 3% of all adults over 40 without diabetes as having the disease.\r
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document.write( " a) Find the probability that a randomly selected adult over 40 does not have diabetes, and is diagnosed as having diabetes (such diagnoses are called \"false positives\").\r
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document.write( " b) Find the probability that a randomly selected adult of 40 is diagnosed as not having diabetes.\r
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document.write( " c) Find the probability that a randomly selected adult over 40 actually has diabetes, given that he/she is diagnosed as not having diabetes (such diagnoses are called \"false negatives\").\r
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document.write( "(Note: it will be helpful to first draw an appropriate tree diagram modeling the situation) \n" );
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Algebra.Com's Answer #849045 by ikleyn(52788)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "It is estimated that approximately 8.37% Americans are afflicted with diabetes. Suppose that a certain diagnostic evaluation for diabetes \n" ); document.write( "will correctly diagnose 98% of all adults over 40 with diabetes as having the disease and incorrectly diagnoses 3% of all adults over 40 \n" ); document.write( "without diabetes as having the disease.\r \n" ); document.write( "\n" ); document.write( "(a) Find the probability that a randomly selected adult over 40 does not have diabetes, and is diagnosed as having diabetes \n" ); document.write( "(such diagnoses are called \"false positives\").\r \n" ); document.write( "\n" ); document.write( "(b) Find the probability that a randomly selected adult \n" ); document.write( "\n" ); document.write( "(c) Find the probability that a randomly selected adult over 40 actually has diabetes, given that he/she is diagnosed as not having diabetes \n" ); document.write( "(such diagnoses are called \"false negatives\"). \n" ); document.write( "~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " In the post by @CPhill, all three parts (a), (b) and (c) are solved and answered INCORRECTLY.\r \n" ); document.write( "\n" ); document.write( " I came to bring correct solutions to all parts.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "(a) In (a), they want you determine the probability of two simultaneous events:\r\n" ); document.write( " the person does not have diabetes, but is diagnosed incorrectly as having diabetes.\r\n" ); document.write( "\r\n" ); document.write( " The ANSWER to (a) is 0.9263*(1-0.98) = 0.018526.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(b) This probability is the sum of two probabilities of disjoint events:\r\n" ); document.write( "\r\n" ); document.write( " - the person does not have diabetes and diagnosed correctly as not having diabetes\r\n" ); document.write( " P1 = 0.9263*0.98;\r\n" ); document.write( "\r\n" ); document.write( " - the person has diabetes, but diagnosed incorrectly as not having diabetes\r\n" ); document.write( " P2 = 0.0837*0.(1-0.03).\r\n" ); document.write( "\r\n" ); document.write( " Therefore, the probability in (b) is P = P1 + P2 = 0.9263*0.98 + 0.0837*(1-0.03) = 0.988963. ANSWER to (b)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(c) In (c), the conditional probability is \r\n" ); document.write( "\r\n" ); document.write( " P =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The goal of this problem is to teach a student to think logically in this specific area. \n" ); document.write( "Having and using common sense is enough to make every step.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Knowing the formal theorems is not required. \n" ); document.write( "Referring to these formal theorems is not required, too. \n" ); document.write( "It only distracts attention from the solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "An example on how incorrectly the problem was solved in the post by @CPhill shows \n" ); document.write( "that the references to formal theorems do not save from making monstrous errors. \n" ); document.write( "Do not save from making monstrous errors at every step.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Common sense should work and really works much better in such simple problems. \n" ); document.write( "And this is exactly my major goal in this post to help students to develop their common sense.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And it should be the major goal of every teaching on how to solve such problems.\r \n" ); document.write( "\n" ); document.write( "And not at all to weave a web of references to theorems in order to demonstrate your knowledgeability.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "About making errors in such problems during their solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I think it is normal to make 5 errors at first attempt; \n" ); document.write( "3 errors at the second trial, 2 errors at the third trial, \n" ); document.write( "1 error at the fourth trial and 0 (zero) errors at fifth trial.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "After that, I would recommend re-solve the problem three more times \n" ); document.write( "to make sure that all errors are just fixed and there are no new errors.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |