document.write( "Question 1192419: Prove that if two intersecting line segments meet at their midpoints, the line
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document.write( "segments joining their endpoints are congruent.
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document.write( "Given: O is the midpoint of XY and of AB
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document.write( "Prove: XA ≅ BY
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Algebra.Com's Answer #848993 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! **1. Definition of Midpoint:**\r \n" ); document.write( "\n" ); document.write( "* Since O is the midpoint of XY, we know that OX ≅ OY. \n" ); document.write( "* Since O is the midpoint of AB, we know that OA ≅ OB.\r \n" ); document.write( "\n" ); document.write( "**2. Vector Addition:**\r \n" ); document.write( "\n" ); document.write( "* Express XA as the sum of vectors: XA = XO + OA \n" ); document.write( "* Express BY as the sum of vectors: BY = BO + OY\r \n" ); document.write( "\n" ); document.write( "**3. Substitute with Equal Vectors**\r \n" ); document.write( "\n" ); document.write( "* Since OX = -OY and OA = -OB, we can substitute: \n" ); document.write( " * XA = -OY + OA \n" ); document.write( " * BY = -OA + OY\r \n" ); document.write( "\n" ); document.write( "**4. Rearrange**\r \n" ); document.write( "\n" ); document.write( "* XA = -OY + OA \n" ); document.write( "* BY = OY - OA\r \n" ); document.write( "\n" ); document.write( "* Observe that XA and BY are the same vector but with opposite signs.\r \n" ); document.write( "\n" ); document.write( "**5. Conclusion**\r \n" ); document.write( "\n" ); document.write( "* Since XA and BY have the same magnitude but opposite directions, they are congruent.\r \n" ); document.write( "\n" ); document.write( "**Therefore, if two intersecting line segments meet at their midpoints, the line segments joining their endpoints are congruent.**\r \n" ); document.write( "\n" ); document.write( "This proof utilizes vector concepts to demonstrate the congruence of the line segments. \n" ); document.write( " \n" ); document.write( " |