document.write( "Question 1192469: A recent article in a leading magazine claimed that the homemakers spend an average of 22 hours per week preparing meals. A director of marketing at a food-processing company surveyed that a recent sample of 28 homemakers resulted in an average time preparation of meals of 17.5 hours per week, with a standard deviation of 4.3 hours. Can the director conclude that the average preparation of meals is lesser? Use 0.05 significance level. \n" ); document.write( "
| Algebra.Com's Answer #848982 by CPhill(1987)     You can put this solution on YOUR website! **1. Set up the Hypotheses**\r \n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H0):** The average time homemakers spend preparing meals is 22 hours per week (μ = 22). \n" ); document.write( "* **Alternative Hypothesis (H1):** The average time homemakers spend preparing meals is less than 22 hours per week (μ < 22).\r \n" ); document.write( "\n" ); document.write( "**2. Calculate the t-statistic**\r \n" ); document.write( "\n" ); document.write( "* **Formula:** \n" ); document.write( " t = (sample mean - population mean) / (sample standard deviation / √sample size) \n" ); document.write( " t = (17.5 - 22) / (4.3 / √28) \n" ); document.write( " t = -4.5 / 0.811 \n" ); document.write( " t ≈ -5.55\r \n" ); document.write( "\n" ); document.write( "**3. Determine the Degrees of Freedom**\r \n" ); document.write( "\n" ); document.write( "* Degrees of Freedom (df) = sample size - 1 = 28 - 1 = 27\r \n" ); document.write( "\n" ); document.write( "**4. Find the Critical Value**\r \n" ); document.write( "\n" ); document.write( "* Since this is a one-tailed test (we're only interested in whether the mean is *less* than 22 hours), we'll use a one-tailed t-distribution table. \n" ); document.write( "* For a significance level of 0.05 and 27 degrees of freedom, the critical t-value is approximately -1.703.\r \n" ); document.write( "\n" ); document.write( "**5. Compare t-statistic to Critical Value**\r \n" ); document.write( "\n" ); document.write( "* The calculated t-statistic (-5.55) is less than the critical t-value (-1.703).\r \n" ); document.write( "\n" ); document.write( "**6. Make a Decision**\r \n" ); document.write( "\n" ); document.write( "* Since the t-statistic falls in the critical region, we **reject the null hypothesis**.\r \n" ); document.write( "\n" ); document.write( "**Conclusion:**\r \n" ); document.write( "\n" ); document.write( "At the 0.05 significance level, there is sufficient evidence to conclude that the average time homemakers spend preparing meals is less than 22 hours per week. \n" ); document.write( " \n" ); document.write( " |