document.write( "Question 1192631: Suppose the times required for a cable company to fix cable problems in its customers’ home are uniformly distributed between 10 minutes and 25 minutes.
\n" ); document.write( "a.What is the probability that a randomly selected cable repair visit will take at least 15 minutes?
\n" ); document.write( "b.What is the probability that a cable repair visit will take over 20 minutes given that it takes over 15 minutes?
\n" ); document.write( "

Algebra.Com's Answer #848960 by CPhill(1987)\"\" \"About 
You can put this solution on YOUR website!
**a. Probability of a visit taking at least 15 minutes**\r
\n" ); document.write( "\n" ); document.write( "* **Uniform Distribution:** In a uniform distribution, the probability density function is constant within the given interval.
\n" ); document.write( "* **Calculate the total interval:**
\n" ); document.write( " * Total interval = 25 minutes - 10 minutes = 15 minutes
\n" ); document.write( "* **Calculate the probability density:**
\n" ); document.write( " * Probability density (f(x)) = 1 / (total interval) = 1 / 15
\n" ); document.write( "* **Calculate the probability of a visit taking at least 15 minutes:**
\n" ); document.write( " * This is the probability of the visit taking between 15 minutes and 25 minutes.
\n" ); document.write( " * Length of this interval: 25 minutes - 15 minutes = 10 minutes
\n" ); document.write( " * Probability = (length of interval) * (probability density) = 10 minutes * (1/15) = 2/3 \r
\n" ); document.write( "\n" ); document.write( "**Therefore, the probability that a randomly selected cable repair visit will take at least 15 minutes is 2/3 or approximately 0.667.**\r
\n" ); document.write( "\n" ); document.write( "**b. Probability of a visit taking over 20 minutes given it takes over 15 minutes**\r
\n" ); document.write( "\n" ); document.write( "* **Conditional Probability:** We are given that the visit takes over 15 minutes. This becomes our new \"total interval.\"
\n" ); document.write( "* **New total interval:** 25 minutes - 15 minutes = 10 minutes
\n" ); document.write( "* **Length of the interval where the visit takes over 20 minutes:** 25 minutes - 20 minutes = 5 minutes
\n" ); document.write( "* **Probability:** 5 minutes / 10 minutes = 1/2\r
\n" ); document.write( "\n" ); document.write( "**Therefore, the probability that a cable repair visit will take over 20 minutes given that it takes over 15 minutes is 1/2 or 0.5.**
\n" ); document.write( "
\n" ); document.write( "
\n" );