document.write( "Question 1192782: . The table below shows the frequency distribution of the masses of 52 female students at a college. Measurements have been recorded to the nearest Kilogram Mass (Kg) Frequency 40-44 3 45-49 2 50-54 7 55-59 18 60-64 18 65-69 3 70-74 1
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\n" ); document.write( "i. Construct a cumulative frequency table and draw a cumulative frequency curve ii. How many students weighed less than 57Kg?
\n" ); document.write( "iii. How many students weighed more than 61Kg?
\n" ); document.write( "iv. 20% were heavier than x Kg. Find the value of
\n" ); document.write( " v. Estimate the median
\n" ); document.write( " vi. Estimate the interquartile range 4. The frequency distribution shows the number of
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Algebra.Com's Answer #848950 by CPhill(1959)\"\" \"About 
You can put this solution on YOUR website!
**i. Construct a Cumulative Frequency Table:**\r
\n" ); document.write( "\n" ); document.write( "| Mass (Kg) | Frequency | Cumulative Frequency |
\n" ); document.write( "|---|---|---|
\n" ); document.write( "| 40-44 | 3 | 3 |
\n" ); document.write( "| 45-49 | 2 | 5 |
\n" ); document.write( "| 50-54 | 7 | 12 |
\n" ); document.write( "| 55-59 | 18 | 30 |
\n" ); document.write( "| 60-64 | 18 | 48 |
\n" ); document.write( "| 65-69 | 3 | 51 |
\n" ); document.write( "| 70-74 | 1 | 52 |\r
\n" ); document.write( "\n" ); document.write( "**ii. How many students weighed less than 57Kg?**\r
\n" ); document.write( "\n" ); document.write( "* From the cumulative frequency table, we see that 30 students weighed less than 57Kg.\r
\n" ); document.write( "\n" ); document.write( "**iii. How many students weighed more than 61Kg?**\r
\n" ); document.write( "\n" ); document.write( "* Total students = 52
\n" ); document.write( "* Students weighing less than or equal to 61Kg = 48 (from the cumulative frequency table)
\n" ); document.write( "* Students weighing more than 61Kg = Total students - Students weighing less than or equal to 61Kg = 52 - 48 = 4 students\r
\n" ); document.write( "\n" ); document.write( "**iv. 20% were heavier than x Kg. Find the value of x**\r
\n" ); document.write( "\n" ); document.write( "* 20% of the students = 0.20 * 52 = 10.4 students
\n" ); document.write( "* Since we are dealing with whole numbers, we can round up to 11 students.
\n" ); document.write( "* From the cumulative frequency table, we can see that 41 students weigh less than or equal to 64Kg.
\n" ); document.write( "* Therefore, 52 - 41 = 11 students weigh more than 64Kg.
\n" ); document.write( "* Hence, x = 64Kg\r
\n" ); document.write( "\n" ); document.write( "**v. Estimate the median**\r
\n" ); document.write( "\n" ); document.write( "* Median is the middle value when the data is arranged in ascending order.
\n" ); document.write( "* Since there are 52 students, the median lies between the 26th and 27th student.
\n" ); document.write( "* From the cumulative frequency table, we see that the 26th and 27th students fall within the 55-59Kg class.
\n" ); document.write( "* **Therefore, the estimated median lies within the 55-59Kg class.**\r
\n" ); document.write( "\n" ); document.write( "**vi. Estimate the interquartile range**\r
\n" ); document.write( "\n" ); document.write( "* **Find the first quartile (Q1):**
\n" ); document.write( " * 25% of 52 students = 13 students
\n" ); document.write( " * Q1 lies within the 50-54Kg class.\r
\n" ); document.write( "\n" ); document.write( "* **Find the third quartile (Q3):**
\n" ); document.write( " * 75% of 52 students = 39 students
\n" ); document.write( " * Q3 lies within the 60-64Kg class.\r
\n" ); document.write( "\n" ); document.write( "* **Estimate the interquartile range (IQR):**
\n" ); document.write( " * IQR = Q3 - Q1
\n" ); document.write( " * IQR ≈ (Upper limit of 60-64Kg class - Lower limit of 50-54Kg class)
\n" ); document.write( " * IQR ≈ 64.5 - 49.5 = 15Kg\r
\n" ); document.write( "\n" ); document.write( "**Note:** These are estimates based on the grouped data. For more precise calculations, you would need the individual weight measurements of each student.\r
\n" ); document.write( "\n" ); document.write( "I hope this helps! Let me know if you have any other questions.
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