document.write( "Question 1192784: A soda machine dispenses soda into 16-ounce cups. Tests shows that the actual amount of soda dispensed has a mean of 15.85 oz and a standard deviation of 9.5 oz. A sample of 12 cups is taken. What is the probability that the sample mean is at most 11.25? \n" ); document.write( "
Algebra.Com's Answer #848949 by CPhill(1987) You can put this solution on YOUR website! **1. Understand the Problem**\r \n" ); document.write( "\n" ); document.write( "* We are given the population mean (μ = 15.85 oz) and standard deviation (σ = 0.95 oz) of the amount of soda dispensed by a machine. \n" ); document.write( "* We have a sample of 12 cups (n = 12). \n" ); document.write( "* We want to find the probability that the sample mean (x̄) is at most 11.25 oz.\r \n" ); document.write( "\n" ); document.write( "**2. Assumptions**\r \n" ); document.write( "\n" ); document.write( "* We assume that the amount of soda dispensed in each cup is normally distributed. \n" ); document.write( "* We assume that the sample is a random sample.\r \n" ); document.write( "\n" ); document.write( "**3. Calculate the Standard Error of the Mean**\r \n" ); document.write( "\n" ); document.write( "* The standard error of the mean (σx̄) is calculated as: \n" ); document.write( " σx̄ = σ / √n \n" ); document.write( " σx̄ = 0.95 / √12 \n" ); document.write( " σx̄ ≈ 0.2739 oz\r \n" ); document.write( "\n" ); document.write( "**4. Standardize the Sample Mean**\r \n" ); document.write( "\n" ); document.write( "* We need to standardize the sample mean using the z-score formula: \n" ); document.write( " z = (x̄ - μ) / σx̄ \n" ); document.write( " z = (11.25 - 15.85) / 0.2739 \n" ); document.write( " z ≈ -16.76\r \n" ); document.write( "\n" ); document.write( "**5. Find the Probability**\r \n" ); document.write( "\n" ); document.write( "* We want to find P(x̄ ≤ 11.25), which is equivalent to finding P(z ≤ -16.76). \n" ); document.write( "* Using a standard normal distribution table or a calculator, we find that P(z ≤ -16.76) is extremely close to 0. \r \n" ); document.write( "\n" ); document.write( "**Conclusion:**\r \n" ); document.write( "\n" ); document.write( "The probability that the sample mean of 12 cups is at most 11.25 oz is extremely low (approximately 0). This suggests that it is very unlikely to obtain such a low sample mean if the true population mean is 15.85 oz. \n" ); document.write( " \n" ); document.write( " |