document.write( "Question 1192908: There are 267 students in faculty and each of them spends approximately 5.625 hours daily in the reading room. Reading room works 8 hours a day. How many seats must be in the reading room that the probability of finding a free seat is not less than 0.78? Use the De Moivre - Laplace theorem \n" ); document.write( "
Algebra.Com's Answer #848947 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! **1. Determine the total student-hours in the reading room:**\r \n" ); document.write( "\n" ); document.write( "* Total student-hours per day = Number of students * Hours per student per day \n" ); document.write( "* Total student-hours per day = 267 students * 5.625 hours/student = 1503.75 student-hours\r \n" ); document.write( "\n" ); document.write( "**2. Calculate the average student-hours per hour of reading room operation:**\r \n" ); document.write( "\n" ); document.write( "* Average student-hours per hour = Total student-hours per day / Reading room hours per day \n" ); document.write( "* Average student-hours per hour = 1503.75 student-hours / 8 hours = 187.96875 student-hours/hour\r \n" ); document.write( "\n" ); document.write( "**3. Determine the minimum number of seats required:**\r \n" ); document.write( "\n" ); document.write( "* We need to find the minimum number of seats (S) such that the probability of finding a free seat is at least 0.78. \n" ); document.write( "* This means the probability of all seats being occupied is at most 1 - 0.78 = 0.22.\r \n" ); document.write( "\n" ); document.write( "* **Using the De Moivre-Laplace Theorem:**\r \n" ); document.write( "\n" ); document.write( " * The De Moivre-Laplace theorem states that for a large number of independent trials (in this case, the number of students using the reading room at any given hour), the binomial distribution can be approximated by a normal distribution.\r \n" ); document.write( "\n" ); document.write( " * We can model the number of students using the reading room at any given hour as a random variable with a binomial distribution. \r \n" ); document.write( "\n" ); document.write( " * Let: \n" ); document.write( " * X = the number of students using the reading room at a given hour \n" ); document.write( " * n = the number of students (267) \n" ); document.write( " * p = the probability that a student is using the reading room at any given hour (p = 5.625 hours/student / 8 hours/day = 0.703125) \n" ); document.write( " * μ = mean of X = n * p = 267 * 0.703125 = 187.96875 \n" ); document.write( " * σ = standard deviation of X = √(n * p * (1 - p)) = √(267 * 0.703125 * 0.296875) ≈ 7.44\r \n" ); document.write( "\n" ); document.write( " * We want to find the minimum number of seats (S) such that: \n" ); document.write( " * P(X > S) ≤ 0.22\r \n" ); document.write( "\n" ); document.write( " * **Standardize:** \n" ); document.write( " * z = (S - μ) / σ \n" ); document.write( " * Find the z-score corresponding to a cumulative probability of 0.78 (since we want P(X > S) ≤ 0.22) in a standard normal distribution table. This z-score is approximately 0.77.\r \n" ); document.write( "\n" ); document.write( " * **Solve for S:** \n" ); document.write( " * 0.77 = (S - 187.96875) / 7.44 \n" ); document.write( " * S = 0.77 * 7.44 + 187.96875 \n" ); document.write( " * S ≈ 193.6\r \n" ); document.write( "\n" ); document.write( "* **Therefore, the minimum number of seats required in the reading room is approximately 194 to ensure that the probability of finding a free seat is not less than 0.78.**\r \n" ); document.write( "\n" ); document.write( "**Note:** This calculation uses the De Moivre-Laplace theorem as an approximation. For a more precise calculation, you could use the binomial distribution directly. However, with a large number of students (n = 267), the normal approximation should provide a reasonably accurate result. \n" ); document.write( " \n" ); document.write( " |