document.write( "Question 1209475: Hi
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document.write( "If Bob reads 25 pages a day he will need one more day to finish a book. If he reads 30 pages a day he will finish 2 days ahead of schedule. How many pages are there in the book.
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Algebra.Com's Answer #848903 by math_tutor2020(3816)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 450 pages\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation \n" ); document.write( "Bob reading at some unknown pace was scheduled to finish the book by day number d. \n" ); document.write( "Him reading at 25 pages per day means he needs an extra day. So he'll finish by day d+1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25(d+1) = total number of pages = p\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If Bob reads 30 pages per day, then he finishes 2 days ahead of schedule. \n" ); document.write( "This means he takes d-2 days to read the same number of pages. \n" ); document.write( "30(d-2) = p \n" ); document.write( "30(d-2) = 25(d+1) ..... plug in p = 25(d+1) \n" ); document.write( "30d-60 = 25d+25 \n" ); document.write( "30d-25d = 25+60 \n" ); document.write( "5d = 85 \n" ); document.write( "d = 85/5 \n" ); document.write( "d = 17 \n" ); document.write( "Bob needs d+1 = 17+1 = 18 days to read the entire book if the pace is 25 pages per day. \n" ); document.write( "There are 25*18 = 450 pages in the book. \n" ); document.write( " \n" ); document.write( " |