document.write( "Question 17582: can some one please show me how to rationalize the denominator in this problem?
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Algebra.Com's Answer #8489 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming that your problem is \"1%2F%282%2B+sqrt%28x%29%29+\".\r
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\n" ); document.write( "\n" ); document.write( "Since this is a binomial denominator (two terms!), you must multiply numerator and denominator by the conjugate of the denominator--that is, the same as the denominator, but with the oppposite sign in the middle.\r
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\n" ); document.write( "\n" ); document.write( "It looks like this:\r
\n" ); document.write( "\n" ); document.write( "\"1%2F%282%2B+sqrt%28x%29%29+\"*\"%282-sqrt%28x%29%29%2F%282-sqrt%28x%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "When you expand the denominator, the middle terms subtract out (as they ALWAYS do!), and the denominator is just \"4+-+x\". This has no radicals, so it is said to be rationalized.\r
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\n" ); document.write( "\n" ); document.write( "Final answer: \"+%282-sqrt%28x%29%29%2F%284-x%29+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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