document.write( "Question 1209461: The line y= mx + c is tangent to the curve x^2 + y^2 = 4. Prove that 4m^2 = c^2 - 4 \n" ); document.write( "
Algebra.Com's Answer #848886 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The graph of x^2+y^2=4 is a circle with center at the origin and radius 2. \n" ); document.write( "Let O be the origin; let A and B be the y- and x-intercepts of the line y=mx+c; and let C be the point of tangency with the circle. \n" ); document.write( "AOB is a right triangle, and OC is the altitude to the hypotenuse. \n" ); document.write( "The y- and x-intercepts of the given line are \n" ); document.write( "A(0,c) \n" ); document.write( "B(c/m,0) \n" ); document.write( "That gives us the lengths of the legs of triangle AOB as \n" ); document.write( "OA = c \n" ); document.write( "OB = c/m \n" ); document.write( "In right triangle ACO, OA = c and OC = 2, so AC = sqrt(c^2-4). \n" ); document.write( "Triangles AOB and ACO are similar. Set up and solve a proportion using the lengths of the legs of those two triangles. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "QED.... \n" ); document.write( " \n" ); document.write( " |