document.write( "Question 1209461: The line y= mx + c is tangent to the curve x^2 + y^2 = 4. Prove that 4m^2 = c^2 - 4 \n" ); document.write( "
Algebra.Com's Answer #848886 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The graph of x^2+y^2=4 is a circle with center at the origin and radius 2.

\n" ); document.write( "Let O be the origin; let A and B be the y- and x-intercepts of the line y=mx+c; and let C be the point of tangency with the circle.

\n" ); document.write( "AOB is a right triangle, and OC is the altitude to the hypotenuse.

\n" ); document.write( "The y- and x-intercepts of the given line are

\n" ); document.write( "A(0,c)
\n" ); document.write( "B(c/m,0)

\n" ); document.write( "That gives us the lengths of the legs of triangle AOB as

\n" ); document.write( "OA = c
\n" ); document.write( "OB = c/m

\n" ); document.write( "In right triangle ACO, OA = c and OC = 2, so AC = sqrt(c^2-4).

\n" ); document.write( "Triangles AOB and ACO are similar. Set up and solve a proportion using the lengths of the legs of those two triangles.

\n" ); document.write( "\"2%2Fsqrt%28c%5E2-4%29=%28c%2Fm%29%2Fc\"

\n" ); document.write( "\"2%2Fsqrt%28c%5E2-4%29=1%2Fm\"
\n" ); document.write( "\"4%2F%28c%5E2-4%29=1%2Fm%5E2\"
\n" ); document.write( "\"c%5E2-4=m%5E2\"

\n" ); document.write( "QED....

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