document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1209450>Question 1209450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle ABC, where |AB| = |AC|, a line CD is drawn from angle C and intersects side AB at D, such that |AD| = |CD| = |BC|. Find the measure of angle A in degrees.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #848863 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3816)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=848863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "This is what the diagram could look like if you follow the steps tutor greenestamps wrote<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%0D%0Adrawing%28400%2C400%2C-4%2C4%2C-3.5%2C4.5%2C%0D%0A%0D%0Aline%280.02%2C3.02%2C-1.62%2C-2%29%2Cline%28-1.62%2C-2%2C1.64389%2C-2.00523%29%2Cline%281.64389%2C-2.00523%2C0.02%2C3.02%29%2Cline%281.64389%2C-2.00523%2C-0.99358%2C-0.08253%29%2C%0D%0A%0D%0Acircle%280.02%2C3.02%2C0.06%29%2Ccircle%280.02%2C3.02%2C0.08%29%2Ccircle%280.02%2C3.02%2C0.1%29%2Ccircle%280.02%2C3.02%2C0.12%29%2Ccircle%28-1.62%2C-2%2C0.06%29%2Ccircle%28-1.62%2C-2%2C0.08%29%2Ccircle%28-1.62%2C-2%2C0.1%29%2Ccircle%28-1.62%2C-2%2C0.12%29%2Ccircle%281.64389%2C-2.00523%2C0.06%29%2Ccircle%281.64389%2C-2.00523%2C0.08%29%2Ccircle%281.64389%2C-2.00523%2C0.1%29%2Ccircle%281.64389%2C-2.00523%2C0.12%29%2Ccircle%28-0.99358%2C-0.08253%2C0.06%29%2Ccircle%28-0.99358%2C-0.08253%2C0.08%29%2Ccircle%28-0.99358%2C-0.08253%2C0.1%29%2Ccircle%28-0.99358%2C-0.08253%2C0.12%29%2C%0D%0A%0D%0Alocate%28-0.1%2C1.9%2C2x%29%2Clocate%280.64%2C-0.74%2C2x%29%2Clocate%280.44-0.2%2C-1.62%2C90-3x%29%2Clocate%28-1.2%2C-1.66%2C90-x%29%2Clocate%28-0.88%2C-0.64%2C90-x%29%2C%0D%0A%0D%0Alocate%280.22%2C3.12%2C%22A%22%29%2Clocate%28-1.72%2C-2.2%2C%22B%22%29%2Clocate%281.84389%2C-2.20523%2C%22C%22%29%2Clocate%28-0.79358-0.6%2C-0.28253%2B0.6%2C%22D%22%29%0D%0A%0D%0A%29%0D%0A ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "From there focus on isosceles triangle BCD to set up the equation<BR>\n" );
document.write( "B+C+D = 180<BR>\n" );
document.write( "(90-x)+(90-3x)+(90-x) = 180<BR>\n" );
document.write( "That equation solves to x = 18, so 2x = 2*18 = <font color=red>36 degrees</font> is the measure of angle A.\r<BR>\n" );
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document.write( "If you prefer tutor ikleyn's approach, then the diagram could look like this\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%0D%0Adrawing%28400%2C400%2C-4%2C4%2C-3.5%2C4.5%2C%0D%0A%0D%0Aline%280.02%2C3.02%2C-1.62%2C-2%29%2Cline%28-1.62%2C-2%2C1.64389%2C-2.00523%29%2Cline%281.64389%2C-2.00523%2C0.02%2C3.02%29%2Cline%281.64389%2C-2.00523%2C-0.99358%2C-0.08253%29%2C%0D%0A%0D%0Acircle%280.02%2C3.02%2C0.06%29%2Ccircle%280.02%2C3.02%2C0.08%29%2Ccircle%280.02%2C3.02%2C0.1%29%2Ccircle%280.02%2C3.02%2C0.12%29%2Ccircle%28-1.62%2C-2%2C0.06%29%2Ccircle%28-1.62%2C-2%2C0.08%29%2Ccircle%28-1.62%2C-2%2C0.1%29%2Ccircle%28-1.62%2C-2%2C0.12%29%2Ccircle%281.64389%2C-2.00523%2C0.06%29%2Ccircle%281.64389%2C-2.00523%2C0.08%29%2Ccircle%281.64389%2C-2.00523%2C0.1%29%2Ccircle%281.64389%2C-2.00523%2C0.12%29%2Ccircle%28-0.99358%2C-0.08253%2C0.06%29%2Ccircle%28-0.99358%2C-0.08253%2C0.08%29%2Ccircle%28-0.99358%2C-0.08253%2C0.1%29%2Ccircle%28-0.99358%2C-0.08253%2C0.12%29%2C%0D%0A%0D%0Alocate%28-0.1%2C1.9%2Cx%29%2Clocate%280.64%2C-0.74%2Cx%29%2Clocate%280.44-0.2%2C-1.62%2Cy-x%29%2Clocate%28-1.2%2C-1.66%2B0.1%2Cy%29%2Clocate%28-0.88%2C-0.64%2Cy%29%2Clocate%28-0.88%2B0.2%2C-0.64%2B0.8%2C180-y%29%2C%0D%0A%0D%0A%0D%0Alocate%280.22%2C3.12%2C%22A%22%29%2Clocate%28-1.72%2C-2.2%2C%22B%22%29%2Clocate%281.84389%2C-2.20523%2C%22C%22%29%2Clocate%28-0.79358-0.6%2C-0.28253%2B0.6%2C%22D%22%29%0D%0A%0D%0A%29%0D%0A ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Triangle ABC gives the equation x+2y = 180<BR>\n" );
document.write( "Triangle BCD gives the equation -x+3y = 180<BR>\n" );
document.write( "Solving that system yields (x,y) = (<font color=red>36</font>, 72)\r<BR>\n" );
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document.write( "Which updates the diagram to<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%0D%0Adrawing%28400%2C400%2C-4%2C4%2C-3.5%2C4.5%2C%0D%0A%0D%0Aline%280.02%2C3.02%2C-1.62%2C-2%29%2Cline%28-1.62%2C-2%2C1.64389%2C-2.00523%29%2Cline%281.64389%2C-2.00523%2C0.02%2C3.02%29%2Cline%281.64389%2C-2.00523%2C-0.99358%2C-0.08253%29%2C%0D%0A%0D%0Acircle%280.02%2C3.02%2C0.06%29%2Ccircle%280.02%2C3.02%2C0.08%29%2Ccircle%280.02%2C3.02%2C0.1%29%2Ccircle%280.02%2C3.02%2C0.12%29%2Ccircle%28-1.62%2C-2%2C0.06%29%2Ccircle%28-1.62%2C-2%2C0.08%29%2Ccircle%28-1.62%2C-2%2C0.1%29%2Ccircle%28-1.62%2C-2%2C0.12%29%2Ccircle%281.64389%2C-2.00523%2C0.06%29%2Ccircle%281.64389%2C-2.00523%2C0.08%29%2Ccircle%281.64389%2C-2.00523%2C0.1%29%2Ccircle%281.64389%2C-2.00523%2C0.12%29%2Ccircle%28-0.99358%2C-0.08253%2C0.06%29%2Ccircle%28-0.99358%2C-0.08253%2C0.08%29%2Ccircle%28-0.99358%2C-0.08253%2C0.1%29%2Ccircle%28-0.99358%2C-0.08253%2C0.12%29%2C%0D%0A%0D%0Alocate%28-0.1-0.1%2C1.9%2Cred%2836%5Eo%29%29%2Clocate%280.64%2C-0.74%2C36%5Eo%29%2Clocate%280.44-0.2%2C-1.62%2B0.2%2C36%5Eo%29%2Clocate%28-1.2%2C-1.66%2B0.2%2C72%5Eo%29%2Clocate%28-0.88%2C-0.64%2C72%5Eo%29%2Clocate%28-0.88%2B0.2%2C-0.64%2B0.9%2C108%5Eo%29%2C%0D%0A%0D%0Alocate%280.22%2C3.12%2C%22A%22%29%2Clocate%28-1.72%2C-2.2%2C%22B%22%29%2Clocate%281.84389%2C-2.20523%2C%22C%22%29%2Clocate%28-0.79358-0.6%2C-0.28253%2B0.6%2C%22D%22%29%0D%0A%0D%0A%29%0D%0A ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "Answer: <font color=red>36 degrees</font>\r<BR>\n" );
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document.write( "Edit: I just realized that ikleyn completely plagiarized her answer. Doesn't surprise me. <BR>\n" );
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