document.write( "Question 1209400: Let a_1, a_2, a_3, \dots be a sequence. If
\n" ); document.write( "a_n = a_{n - 1} + a_{n - 2}
\n" ); document.write( "for all n \ge 3, and a_{11} = 4 and a_{10} = 1, then find a_6.
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Algebra.Com's Answer #848756 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "I doubt if there is a faster way to solve the problem than what is shown by the other tutor... but his response has a lot of unnecessary discussion at the beginning.

\n" ); document.write( "The given recursive formula tells us how to get the next numbers in the sequence from the previous numbers in the sequence:

\n" ); document.write( "a_n = a_(n-1) + a_(n-2)

\n" ); document.write( "Turn that recursive formula around so it tells you how to find PREVIOUS numbers in the sequence from known numbers in the sequence:

\n" ); document.write( "a_(n-2) = a_n - a_(n-1)

\n" ); document.write( "Then, starting with the given a_11 = 4 and a_10 = 1...

\n" ); document.write( "a_9 = a_11 - a_10 = 4-1 = 3

\n" ); document.write( "a_8 = a_10 - a_9 = 1-3 = -2

\n" ); document.write( "a_7 = a_9 - a_8 = 3-(-2) = 5

\n" ); document.write( "a_6 = a_8 - a_7 = -2-5 = -7

\n" ); document.write( "ANSWER: a_6 = -7
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