document.write( "Question 1209402: how much water to add to 4oz of 99.9 DMSO to make it 70 % \n" ); document.write( "

Algebra.Com's Answer #848754 by ikleyn(52778) $\"\"$ $\"About$

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\n" ); document.write( "how much water to add to 4oz of 99.9% DMSO to make it 70 % ?
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document.write( "In this mixture, 99.9% of volume is pure DNSO.\r\n" );
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document.write( "So, the volume of the pure DMSO is 4*0.999 oz = 3.996 oz.\r\n" );
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document.write( "We want this volume, 3.996 oz, be 70%, or 0.7, of the new volume  V of the mixture.\r\n" );
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document.write( "So, we write  0.7*V = 3.996 oz.\r\n" );
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document.write( "It gives  V =  = 5.708571429 oz.\r\n" );
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document.write( "It means that the volume  5.708571429 - 4 = 1.708571429 oz of water should be added.\r\n" );
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document.write( "You may round it to  1.71 oz of water.    ANSWER\r\n" );
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