document.write( "Question 1209400: Let a_1, a_2, a_3, \dots be a sequence. If
\n" ); document.write( "a_n = a_{n - 1} + a_{n - 2}
\n" ); document.write( "for all n \ge 3, and a_{11} = 4 and a_{10} = 1, then find a_6.
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Algebra.Com's Answer #848753 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "a3 = a2+a1
\n" ); document.write( "a4 = a3+a2
\n" ); document.write( "a5 = a4+a3
\n" ); document.write( "a6 = a5+a4
\n" ); document.write( "... etc ...
\n" ); document.write( "a11 = a10+a9
\n" ); document.write( "The indices decrease when reading left to right.\r
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\n" ); document.write( "\n" ); document.write( "Let's rearrange each equation so that the last term on the right hand side is by itself.
\n" ); document.write( "a1 = a3-a2
\n" ); document.write( "a2 = a4-a3
\n" ); document.write( "a3 = a5-a4
\n" ); document.write( "a4 = a6-a5
\n" ); document.write( "... etc ...
\n" ); document.write( "a9 = a11-a10
\n" ); document.write( "The template is a_n = a_{n+2} - a_{n+1}\r
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\n" ); document.write( "\n" ); document.write( "Since we are given a11 = 4 and a10 = 1, we can then say,
\n" ); document.write( "a9 = a11-a10
\n" ); document.write( "a9 = 4-1
\n" ); document.write( "a9 = 3
\n" ); document.write( "Then,
\n" ); document.write( "a8 = a10-a9
\n" ); document.write( "a8 = 1-3
\n" ); document.write( "a8 = -2
\n" ); document.write( "And,
\n" ); document.write( "a7 = a9-a8
\n" ); document.write( "a7 = 3-(-2)
\n" ); document.write( "a7 = 3+2
\n" ); document.write( "a7 = 5
\n" ); document.write( "And,
\n" ); document.write( "a6 = a8-a7
\n" ); document.write( "a6 = -2-5
\n" ); document.write( "a6 = -7\r
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\n" ); document.write( "\n" ); document.write( "There might be a faster more efficient approach.
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