document.write( "Question 1209392: In class, we derived that
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document.write( "\frac{1}{n(n + 1)} = \frac{1}{n} - \frac{1}{n + 1}.\r
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document.write( "Fill in the blanks to make a true equation:\r
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document.write( "\frac{5x}{(x - 1)(x^2 + 2)(x + 7)^3)} = \frac{A}{x - 1} + \frac{Bx + C}{x^2 + 2} + \frac{D}{x + 7} + \frac{E}{(x + 7)^2} + \frac{F}{(x + 7)^3} \n" );
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Algebra.Com's Answer #848747 by Edwin McCravy(20059)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Since there are no blanks, perhaps you meant to find values of A thru F that\r\n" ); document.write( "would make this equation an identity.\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |