document.write( "Question 1209383: Prove that n^2-n is always even \n" ); document.write( "
Algebra.Com's Answer #848735 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The statement of the problem is deficient; n^2-n is NOT always even. It is always even IF n IS AN INTEGER. \n" ); document.write( "n^2-n = n(n-1) \n" ); document.write( "If n is an integer, then that expression is the product of two consecutive integers. In any two consecutive integers, one of them is odd and the other is even; and the product of two integers is even whenever at least one of them is even. \n" ); document.write( "So the product of two consecutive integers is always even. \n" ); document.write( "TRUE: n^2-n is always even if n is an integer \n" ); document.write( " \n" ); document.write( " |