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document.write( "If a loan of ₱60,000 is to be settled by 3,200 monthly payments for 2
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document.write( "years, what interest rate compounded monthly is charged on the loan?
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document.write( " The solution in the post by the other tutor is WRONG.\r
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document.write( " So, I came to bring a correct solution.\r
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document.write( "Write a loan equation\r\n" );
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document.write( " M =
,\r\n" );
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document.write( "where \r\n" );
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document.write( "M is the monthly payment;\r\n" );
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document.write( "L is the loaned amount;\r\n" );
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document.write( "r is the monthly effective rate as a decimal;\r\n" );
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document.write( "n is the number of payments (= the number of months).\r\n" );
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document.write( "In our case this equation takes the form\r\n" );
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document.write( " 3200 =
,\r\n" );
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document.write( "or\r\n" );
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=
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document.write( " 0.053333333 =
.\r\n" );
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document.write( "In this equation, r is the unknown.\r\n" );
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document.write( "Such equation is unsolvable algebraically, so use the numerical methods.\r\n" );
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document.write( "You may use any of numerous online calculators.\r\n" );
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document.write( "I used DESMOS at www.desmos.com/calculator\r\n" );
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document.write( "It gave me r = 0.02077, approximately.\r\n" );
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document.write( " Here is the link to the DESMOS solution. \r\n" );
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document.write( " https://www.desmos.com/calculator/aivq2p1eli\r\n" );
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document.write( " Click on the intersection point to get its coordinates.\r\n" );
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document.write( "This value r = 0.02077 is the monthly effective rate - - - so, the annual nominal rate is 12 times this value\r\n" );
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= 12*0.02077 = 0.24924, or about 0.25,\r\n" );
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document.write( "which corresponds to 25%.\r\n" );
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document.write( "ANSWER. In this problem, the annual interest rate is about 25% compounded monthly.\r\n" );
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document.write( " Surely, from the usual common sense, this rate is extremely high,\r\n" );
document.write( " but it tells only that this problem is Math - - - not from real life.\r\n" );
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document.write( "Solved.\r
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document.write( "To check my solution, I substituted this value r= 0.02077\r\n" );
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document.write( "into the loan function f(r) =
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document.write( "It returns the value 0.053333396, which is quite close to 0.053333333, so my solution is confirmed.\r\n" );
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document.write( "To check the solution from the other tutor, I substituted his value r= 0.01\r\n" );
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document.write( "into the loan function f(r) =
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document.write( "It returns the value 0.047073, which is not close to
= 0.053333333.\r\n" );
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document.write( "So, the other's tutor solution is wrong, which is confirmed.\r\n" );
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