document.write( "Question 1193539: (1) The weight of cement bags produced in a cement company follow normal distribution
\n" ); document.write( "whose population is infinite. The expected mean of weight of the cement bags for sales of
\n" ); document.write( "this population is 45KG and its variance is unknown. The sales manager of the firm
\n" ); document.write( "claims that the mean weight of the cement bags is significantly more than the expected
\n" ); document.write( "mean weight of the population. So, he has selected a random sample of 36 bags and its
\n" ); document.write( "mean and variance are found to be 44KG and 1.25KG, respectively. Verify the intuition
\n" ); document.write( "of the sales manager at a significance level of 0.05. \r
\n" ); document.write( "\n" ); document.write( "(2) The quality manager of a washing machine company feels that the mean time between
\n" ); document.write( "failures of the motors received is at most 90 days. The quality manager wants to test his
\n" ); document.write( "intuition. Hence, he has taken a sample of 25 motors whose mean time between failure
\n" ); document.write( "and its variance are found to be 93 days and 16 days, respectively. Verify the intuition of
\n" ); document.write( "the quality manager at a significance level of 0.05.
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Algebra.Com's Answer #848650 by ElectricPavlov(122)\"\" \"About 
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Certainly, let's analyze both scenarios.\r
\n" ); document.write( "\n" ); document.write( "**1. Cement Bag Weights**\r
\n" ); document.write( "\n" ); document.write( "**a) Set up Hypotheses**\r
\n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H0):** The mean weight of the cement bags is less than or equal to the expected mean weight.
\n" ); document.write( " * μ ≤ 45 kg
\n" ); document.write( "* **Alternative Hypothesis (H1):** The mean weight of the cement bags is significantly greater than the expected mean weight.
\n" ); document.write( " * μ > 45 kg\r
\n" ); document.write( "\n" ); document.write( "**b) Choose the Test Statistic**\r
\n" ); document.write( "\n" ); document.write( "* Since the population variance is unknown and the sample size is greater than 30, we can use the **one-sample t-test**.\r
\n" ); document.write( "\n" ); document.write( "**c) Calculate the Test Statistic**\r
\n" ); document.write( "\n" ); document.write( "* **Given:**
\n" ); document.write( " * Sample size (n): 36
\n" ); document.write( " * Sample mean (x̄): 44 kg
\n" ); document.write( " * Sample variance (s²): 1.25 kg²
\n" ); document.write( " * Population mean (μ₀): 45 kg
\n" ); document.write( "* **Calculate the standard error:**
\n" ); document.write( " * Standard Error (SE) = s / √n
\n" ); document.write( " * SE = √(1.25) / √36
\n" ); document.write( " * SE ≈ 0.2041
\n" ); document.write( "* **Calculate the t-score:**
\n" ); document.write( " * t = (x̄ - μ₀) / SE
\n" ); document.write( " * t = (44 - 45) / 0.2041
\n" ); document.write( " * t ≈ -4.898\r
\n" ); document.write( "\n" ); document.write( "**d) Determine Critical Value**\r
\n" ); document.write( "\n" ); document.write( "* **Significance Level:** α = 0.05
\n" ); document.write( "* **Degrees of Freedom (df):** n - 1 = 36 - 1 = 35
\n" ); document.write( "* **One-tailed test (right-tailed):** Find the critical t-value from a t-distribution table.
\n" ); document.write( " * t_critical ≈ 1.690\r
\n" ); document.write( "\n" ); document.write( "**e) Decision Rule**\r
\n" ); document.write( "\n" ); document.write( "* If the calculated t-score is greater than the critical t-value, reject the null hypothesis.
\n" ); document.write( "* If the calculated t-score is less than or equal to the critical t-value, fail to reject the null hypothesis.\r
\n" ); document.write( "\n" ); document.write( "**f) Make a Decision**\r
\n" ); document.write( "\n" ); document.write( "* Our calculated t-score (-4.898) is less than the critical t-value (1.690).\r
\n" ); document.write( "\n" ); document.write( "* **Conclusion:** We fail to reject the null hypothesis.\r
\n" ); document.write( "\n" ); document.write( "**Interpretation**\r
\n" ); document.write( "\n" ); document.write( "The evidence does not support the sales manager's claim that the mean weight of the cement bags is significantly greater than the expected mean weight.\r
\n" ); document.write( "\n" ); document.write( "**2. Washing Machine Motor Time Between Failures**\r
\n" ); document.write( "\n" ); document.write( "**a) Set up Hypotheses**\r
\n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H0):** The mean time between failures is less than or equal to 90 days.
\n" ); document.write( " * μ ≤ 90 days
\n" ); document.write( "* **Alternative Hypothesis (H1):** The mean time between failures is greater than 90 days.
\n" ); document.write( " * μ > 90 days\r
\n" ); document.write( "\n" ); document.write( "**b) Choose the Test Statistic**\r
\n" ); document.write( "\n" ); document.write( "* Similar to the first scenario, we can use the **one-sample t-test** since the population variance is unknown.\r
\n" ); document.write( "\n" ); document.write( "**c) Calculate the Test Statistic**\r
\n" ); document.write( "\n" ); document.write( "* **Given:**
\n" ); document.write( " * Sample size (n): 25
\n" ); document.write( " * Sample mean (x̄): 93 days
\n" ); document.write( " * Sample variance (s²): 16 days²
\n" ); document.write( " * Population mean (μ₀): 90 days
\n" ); document.write( "* **Calculate the standard error:**
\n" ); document.write( " * SE = s / √n
\n" ); document.write( " * SE = √(16) / √25
\n" ); document.write( " * SE = 4 / 5
\n" ); document.write( " * SE = 0.8 days
\n" ); document.write( "* **Calculate the t-score:**
\n" ); document.write( " * t = (x̄ - μ₀) / SE
\n" ); document.write( " * t = (93 - 90) / 0.8
\n" ); document.write( " * t = 3 / 0.8
\n" ); document.write( " * t = 3.75\r
\n" ); document.write( "\n" ); document.write( "**d) Determine Critical Value**\r
\n" ); document.write( "\n" ); document.write( "* **Significance Level:** α = 0.05
\n" ); document.write( "* **Degrees of Freedom (df):** n - 1 = 25 - 1 = 24
\n" ); document.write( "* **One-tailed test (right-tailed):** Find the critical t-value from a t-distribution table.
\n" ); document.write( " * t_critical ≈ 1.711\r
\n" ); document.write( "\n" ); document.write( "**e) Decision Rule**\r
\n" ); document.write( "\n" ); document.write( "* If the calculated t-score is greater than the critical t-value, reject the null hypothesis.
\n" ); document.write( "* If the calculated t-score is less than or equal to the critical t-value, fail to reject the null hypothesis.\r
\n" ); document.write( "\n" ); document.write( "**f) Make a Decision**\r
\n" ); document.write( "\n" ); document.write( "* Our calculated t-score (3.75) is greater than the critical t-value (1.711).\r
\n" ); document.write( "\n" ); document.write( "* **Conclusion:** We reject the null hypothesis.\r
\n" ); document.write( "\n" ); document.write( "**Interpretation**\r
\n" ); document.write( "\n" ); document.write( "The evidence supports the quality manager's intuition that the mean time between failures of the motors is significantly greater than 90 days.
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