document.write( "Question 1193540: (a) The regional manager of a bank wants to analyze the number of delayed repayments of
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document.write( "instalments of consumer loans in two of its branch banks (Branch −X and Branch −Y ).
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document.write( "The number of delayed payments of instalments in each branch bank follows normal
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document.write( "distribution. The manager feels that the number of delayed payments of instalments by
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document.write( "the consumers of the Branch −X is no way different from that of the Branch −Y . So, he
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document.write( "selected the loan accounts of 80 different consumers from the Branch −X and found that
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document.write( "the mean and variance of the number of delayed payments of instalments are 35 and 25,
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document.write( "respectively. Similarly, he selected the loan accounts of 100 different consumers from the Branch −Y and found that the mean and variance of the number of delayed payments of
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document.write( "instalments are 40 and 49, respectively. Test his intuition at a significance level of 0.01. \n" );
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Algebra.Com's Answer #848649 by ElectricPavlov(122)![]() ![]() ![]() You can put this solution on YOUR website! **1. Set up Hypotheses**\r \n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H0):** The mean number of delayed payments of installments is the same for both branches. \n" ); document.write( " * μ₁ = μ₂ \n" ); document.write( "* **Alternative Hypothesis (H1):** The mean number of delayed payments of installments is different for the two branches. \n" ); document.write( " * μ₁ ≠ μ₂\r \n" ); document.write( "\n" ); document.write( "**2. Choose the Test Statistic**\r \n" ); document.write( "\n" ); document.write( "* Since we are comparing the means of two independent samples with known (or assumed) population variances, we will use the **Z-test for the difference between two means**.\r \n" ); document.write( "\n" ); document.write( "**3. Calculate the Test Statistic**\r \n" ); document.write( "\n" ); document.write( "* **Given:** \n" ); document.write( " * Sample 1 (Branch X): n₁ = 80, x̄₁ = 35, σ₁² = 25 \n" ); document.write( " * Sample 2 (Branch Y): n₂ = 100, x̄₂ = 40, σ₂² = 49 \n" ); document.write( "* **Calculate the pooled variance (not needed in this case since population variances are known):** \n" ); document.write( " * Pooled variance (s_p²) = [(n₁ - 1)s₁² + (n₂ - 1)s₂²] / (n₁ + n₂ - 2) \n" ); document.write( "* **Calculate the standard error of the difference between means:** \n" ); document.write( " * SE = √[(σ₁²/n₁) + (σ₂²/n₂)] \n" ); document.write( " * SE = √[(25/80) + (49/100)] \n" ); document.write( " * SE = √(0.3125 + 0.49) \n" ); document.write( " * SE = √0.8025 \n" ); document.write( " * SE ≈ 0.8958\r \n" ); document.write( "\n" ); document.write( "* **Calculate the Z-score:** \n" ); document.write( " * Z = (x̄₁ - x̄₂) / SE \n" ); document.write( " * Z = (35 - 40) / 0.8958 \n" ); document.write( " * Z = -5 / 0.8958 \n" ); document.write( " * Z ≈ -5.58\r \n" ); document.write( "\n" ); document.write( "**4. Determine Critical Values**\r \n" ); document.write( "\n" ); document.write( "* **Significance Level:** α = 0.01 \n" ); document.write( "* **Two-tailed test:** We need to find the critical values for both tails of the standard normal distribution. \n" ); document.write( "* **Using a standard normal distribution table or statistical software:** \n" ); document.write( " * Critical values: Z_critical ≈ ±2.576\r \n" ); document.write( "\n" ); document.write( "**5. Decision Rule**\r \n" ); document.write( "\n" ); document.write( "* If the calculated Z-score (|Z|) is greater than the critical value (Z_critical), reject the null hypothesis. \n" ); document.write( "* If the calculated Z-score (|Z|) is less than or equal to the critical value (Z_critical), fail to reject the null hypothesis.\r \n" ); document.write( "\n" ); document.write( "**6. Make a Decision**\r \n" ); document.write( "\n" ); document.write( "* Our calculated Z-score (|-5.58|) is greater than the critical value (2.576).\r \n" ); document.write( "\n" ); document.write( "* **Conclusion:** We reject the null hypothesis.\r \n" ); document.write( "\n" ); document.write( "**Interpretation**\r \n" ); document.write( "\n" ); document.write( "The evidence suggests that the mean number of delayed payments of installments is significantly different between Branch X and Branch Y at the 0.01 significance level. \r \n" ); document.write( "\n" ); document.write( "**Therefore, the manager's intuition that the number of delayed payments is the same for both branches is not supported by the data.** \n" ); document.write( " \n" ); document.write( " |