document.write( "Question 1193541: The weight of a drug produced by a pharmaceutical company follows normal
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document.write( "distribution. The specified variances of the weight of the drug of this population is
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document.write( "0.36KG. The quality engineer of the firm claims that the variance of the weight of the
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document.write( "drug does not differ significantly from the specified variance of the weight of the drug of
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document.write( "the population. So, the purchase manager of a hospital who places order for the drug with
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document.write( "the pharmaceutical company has selected a random sample of 15 drugs. The variance of
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document.write( "the weight of the sample is found to be 0.05KG. Verify the intuition of the quality
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document.write( "engineer of the pharmaceutical company at a significance level of 0.05. \n" );
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Algebra.Com's Answer #848648 by ElectricPavlov(122)![]() ![]() ![]() You can put this solution on YOUR website! **1. Set up Hypotheses**\r \n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H0):** The variance of the drug weight in the sample is equal to the specified population variance. \n" ); document.write( " * σ² = 0.36 kg² \r \n" ); document.write( "\n" ); document.write( "* **Alternative Hypothesis (H1):** The variance of the drug weight in the sample is different from the specified population variance. \n" ); document.write( " * σ² ≠ 0.36 kg²\r \n" ); document.write( "\n" ); document.write( "**2. Test Statistic**\r \n" ); document.write( "\n" ); document.write( "* We will use the chi-square test statistic for this hypothesis test:\r \n" ); document.write( "\n" ); document.write( " χ² = (n - 1) * s² / σ² \r \n" ); document.write( "\n" ); document.write( " where: \n" ); document.write( " * n is the sample size (15) \n" ); document.write( " * s² is the sample variance (0.05 kg²) \n" ); document.write( " * σ² is the population variance (0.36 kg²)\r \n" ); document.write( "\n" ); document.write( "**3. Calculate Test Statistic**\r \n" ); document.write( "\n" ); document.write( "χ² = (15 - 1) * 0.05 / 0.36 \n" ); document.write( "χ² = 14 * 0.05 / 0.36 \n" ); document.write( "χ² ≈ 1.94\r \n" ); document.write( "\n" ); document.write( "**4. Determine Critical Values**\r \n" ); document.write( "\n" ); document.write( "* **Degrees of Freedom:** df = n - 1 = 15 - 1 = 14 \n" ); document.write( "* **Significance Level:** α = 0.05 \n" ); document.write( "* **Two-tailed test:** We need to find the critical values for both tails of the chi-square distribution.\r \n" ); document.write( "\n" ); document.write( "* **Find critical values using a chi-square table or statistical software:** \n" ); document.write( " * Lower critical value (χ²_lower) ≈ 5.629 \n" ); document.write( " * Upper critical value (χ²_upper) ≈ 26.119\r \n" ); document.write( "\n" ); document.write( "**5. Decision Rule**\r \n" ); document.write( "\n" ); document.write( "* If the calculated chi-square statistic (χ²) falls within the critical region (below χ²_lower or above χ²_upper), we reject the null hypothesis. \n" ); document.write( "* If the calculated chi-square statistic falls within the acceptance region (between χ²_lower and χ²_upper), we fail to reject the null hypothesis.\r \n" ); document.write( "\n" ); document.write( "**6. Make a Decision**\r \n" ); document.write( "\n" ); document.write( "* Our calculated χ² (1.94) is less than the lower critical value (5.629). \r \n" ); document.write( "\n" ); document.write( "* **Conclusion:** We reject the null hypothesis. \r \n" ); document.write( "\n" ); document.write( "**Interpretation**\r \n" ); document.write( "\n" ); document.write( "The evidence suggests that the variance of the drug weight in the sample is significantly different from the specified population variance at the 0.05 significance level. \r \n" ); document.write( "\n" ); document.write( "**Therefore, the quality engineer's claim that the variance of the drug weight does not differ significantly from the specified variance is not supported by the sample data.** \n" ); document.write( " \n" ); document.write( " |