document.write( "Question 1193583: You want to obtain a sample to estimate the average number of hours per week community college students in the United States work at their job while being a full-time student. Based on previous evidence, you believe the population standard deviation is 10. You would like to be 99% confident that your estimate is within 1.5 hours of the true population mean.
\n" ); document.write( "Assume that the number of statistics students is unknown, but very large. How large of a sample size is required?
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Algebra.Com's Answer #848643 by yurtman(42)\"\" \"About 
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**1. Define the parameters:**\r
\n" ); document.write( "\n" ); document.write( "* **Confidence level:** 99%
\n" ); document.write( "* **Margin of error (E):** 1.5 hours
\n" ); document.write( "* **Population standard deviation (σ):** 10 hours\r
\n" ); document.write( "\n" ); document.write( "**2. Find the Z-score:**\r
\n" ); document.write( "\n" ); document.write( "* For a 99% confidence level, the Z-score is 2.576 (found using a standard normal distribution table or calculator).\r
\n" ); document.write( "\n" ); document.write( "**3. Calculate the required sample size (n):**\r
\n" ); document.write( "\n" ); document.write( "* Use the formula:
\n" ); document.write( " n = (Z-score * σ / E)²
\n" ); document.write( "* Substitute the values:
\n" ); document.write( " n = (2.576 * 10 / 1.5)²
\n" ); document.write( "* Calculate:
\n" ); document.write( " n ≈ 294.81\r
\n" ); document.write( "\n" ); document.write( "**4. Round up:**\r
\n" ); document.write( "\n" ); document.write( "* Since we can't have a fraction of a student, round up the sample size to the nearest whole number.\r
\n" ); document.write( "\n" ); document.write( "**Therefore, a sample size of 295 community college students is required to be 99% confident that the estimate of the average number of hours worked per week is within 1.5 hours of the true population mean.**
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