document.write( "Question 1209350: Rama was getting some items for the new school year. First, he bought some textbooks with $8 more than 1/3 of his money. Next, Next, he bought his stationery with $12.20 less than 1/2 of his remaining money. Lastly, he bought some school socks with $2.80 more than 1/2 of the money left. Then, he had $15.40 with him. How much money did he have at first? \n" ); document.write( "
Algebra.Com's Answer #848603 by proyaop(69)![]() ![]() ![]() You can put this solution on YOUR website! **1. Let's represent:**\r \n" ); document.write( "\n" ); document.write( "* The initial amount of money Rama had as 'x'\r \n" ); document.write( "\n" ); document.write( "**2. Formulate the equation:**\r \n" ); document.write( "\n" ); document.write( "* **Textbooks:** Rama spent (x/3) + 8 dollars on textbooks. \n" ); document.write( "* **Remaining money after textbooks:** x - (x/3) - 8 = (2/3)x - 8 \n" ); document.write( "* **Stationery:** Rama spent 1/2 * ((2/3)x - 8) - 12.20 dollars on stationery. \n" ); document.write( "* **Remaining money after stationery:** (2/3)x - 8 - 1/2 * ((2/3)x - 8) + 12.20 = (2/3)x - 8 - (1/3)x + 4 + 12.20 = (1/3)x + 8.20 \n" ); document.write( "* **School Socks:** Rama spent 1/2 * ((1/3)x + 8.20) + 2.80 dollars on socks. \n" ); document.write( "* **Remaining money:** (1/3)x + 8.20 - 1/2 * ((1/3)x + 8.20) - 2.80 = 15.40\r \n" ); document.write( "\n" ); document.write( "**3. Simplify and solve the equation:**\r \n" ); document.write( "\n" ); document.write( "* (1/3)x + 8.20 - (1/6)x - 4.10 - 2.80 = 15.40 \n" ); document.write( "* (1/6)x + 1.30 = 15.40 \n" ); document.write( "* (1/6)x = 14.10 \n" ); document.write( "* x = 14.10 * 6 \n" ); document.write( "* x = 84.60\r \n" ); document.write( "\n" ); document.write( "**Therefore, Rama had $84.60 at first.** \n" ); document.write( " \n" ); document.write( " |