document.write( "Question 1209347: We cut a regular octagon ABCDEFGH out of a piece of cardboard. If $AB = 1$, then what is the area of the octagon?
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Algebra.Com's Answer #848585 by ikleyn(52776)\"\" \"About 
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\n" ); document.write( "We cut a regular octagon ABCDEFGH out of a piece of cardboard.
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document.write( "Let R be the radius of the circumscribed circle around our octagon.\r\n" );
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document.write( "Let's find its radius via the side length s.\r\n" );
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document.write( "The octagon consists of 8 congruent isosceles triangles, having \r\n" );
document.write( "the common vertex in the center.\r\n" );
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document.write( "Each such a triangle is an isosceles triangle with the lateral sides of the length R\r\n" );
document.write( "and the angle at the vertex of 45°.  Write the cosine rule equation for such a triangle \r\n" );
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document.write( "    \"s%5E2\" = \"R%5E2\" + \"R%5E2\" - \"2%2AR%2AR%2Acos%2845%5Eo%29\",\r\n" );
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document.write( "    \"s%5E2\" = \"2R%5E2%2A%281-cos%2845%5Eo%29%29\",\r\n" );
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document.write( "    \"R%5E2\" = \"s%5E2%2F%282%2A%281-cos%2845%5Eo%29%29%29\".    (1)\r\n" );
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document.write( "In our case with s = 1, the last formula takes the form\r\n" );
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document.write( "    \"R%5E2\" = \"1%2F%282%2A%281-cos%2845%5Eo%29%29%29\" = \"1%2F%282%2A%281-sqrt%282%29%2F2%29%29%29\" = \"2%2F%282%2A%282-sqrt%282%29%29%29\" = \"1%2F%282-sqrt%282%29%29\" = \"%282%2Bsqrt%282%29%29%2F%284-2%29\" = \"%282%2Bsqrt%282%29%29%2F2\".    (2)\r\n" );
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document.write( "Now the area of one such a triangle is\r\n" );
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document.write( "    \"area%5Btriangle%5D\" = \"%281%2F2%29%2AR%2AR%2Asin%2845%5Eo%29\" = \"%281%2F2%29%2AR%5E2%2Asin%2845%5Eo%29\" = \"%281%2F2%29%2A%28%282%2Bsqrt%282%29%29%2F2%29%2A%28sqrt%282%29%2F2%29\" = \"%282%2Asqrt%282%29%2B2%29%2F8\" = \"%28sqrt%282%29%2B1%29%2F4\".    (3)\r\n" );
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document.write( "For the area of the entire octagon, we should take the quantity (3)  8 (eight) times to get\r\n" );
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document.write( "    \"area%5Boctagon%5D\" = \"2+%2B+2%2Asqrt%282%29\"  square units.    ANSWER\r\n" );
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