document.write( "Question 1193979: A researcher is investigating the relationship between academic performance and self-esteem. A sample of 150 ten-year old
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document.write( "children is obtained, and each child is classified by level of academic performance and level of self-esteem. Test at 0.05 level of
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document.write( "significance.
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document.write( "Level of acad
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document.write( "performance/ level
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document.write( "of self esteem. High. Medium. Low
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document.write( " High 17. 32. 11
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document.write( " Low. 13. 43. 34 \n" );
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Algebra.Com's Answer #848542 by parmen(42)![]() ![]() ![]() You can put this solution on YOUR website! **1. Set up Hypotheses**\r \n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H0):** There is no association between academic performance and self-esteem in the population of ten-year-old children. \n" ); document.write( "* **Alternative Hypothesis (H1):** There is an association between academic performance and self-esteem in the population of ten-year-old children.\r \n" ); document.write( "\n" ); document.write( "**2. Calculate Expected Frequencies**\r \n" ); document.write( "\n" ); document.write( "* **Create a table of expected frequencies:** \n" ); document.write( " | Level of Academic Performance | High Self-Esteem | Medium Self-Esteem | Low Self-Esteem | Row Total | \n" ); document.write( " |---|---|---|---|---| \n" ); document.write( " | High | (60*60)/150 = 24 | (60*75)/150 = 30 | (60*15)/150 = 18 | 60 | \n" ); document.write( " | Low | (90*60)/150 = 36 | (90*75)/150 = 45 | (90*15)/150 = 27 | 90 | \n" ); document.write( " | Column Total | 60 | 75 | 15 | 150 |\r \n" ); document.write( "\n" ); document.write( "* **Where:** \n" ); document.write( " * Row Total: Total number of children in each academic performance level. \n" ); document.write( " * Column Total: Total number of children in each self-esteem level. \n" ); document.write( " * Grand Total: Total number of children in the sample (150).\r \n" ); document.write( "\n" ); document.write( "**3. Calculate the Chi-Square Test Statistic**\r \n" ); document.write( "\n" ); document.write( "* **Formula:** χ² = Σ [(O - E)² / E] \n" ); document.write( " * Where: \n" ); document.write( " * O = Observed frequency in each cell \n" ); document.write( " * E = Expected frequency in each cell\r \n" ); document.write( "\n" ); document.write( "* **Calculate for each cell:** \n" ); document.write( " * (17-24)²/24 = 2.04 \n" ); document.write( " * (32-30)²/30 = 0.13 \n" ); document.write( " * (11-18)²/18 = 2.72 \n" ); document.write( " * (13-36)²/36 = 12.5 \n" ); document.write( " * (43-45)²/45 = 0.09 \n" ); document.write( " * (34-27)²/27 = 1.70\r \n" ); document.write( "\n" ); document.write( "* **Sum the values:** χ² = 2.04 + 0.13 + 2.72 + 12.5 + 0.09 + 1.70 = 19.18\r \n" ); document.write( "\n" ); document.write( "**4. Determine the Degrees of Freedom**\r \n" ); document.write( "\n" ); document.write( "* Degrees of Freedom (df) = (Number of rows - 1) * (Number of columns - 1) = (2 - 1) * (3 - 1) = 2\r \n" ); document.write( "\n" ); document.write( "**5. Find the Critical Value**\r \n" ); document.write( "\n" ); document.write( "* Using a chi-square distribution table, find the critical value for α = 0.05 and df = 2. \n" ); document.write( "* The critical value is approximately 5.991.\r \n" ); document.write( "\n" ); document.write( "**6. Make a Decision**\r \n" ); document.write( "\n" ); document.write( "* **Compare the calculated chi-square statistic to the critical value:** \n" ); document.write( " * 19.18 > 5.991\r \n" ); document.write( "\n" ); document.write( "* **Decision:** Since the calculated chi-square statistic (19.18) is greater than the critical value (5.991), we reject the null hypothesis.\r \n" ); document.write( "\n" ); document.write( "**7. Conclusion**\r \n" ); document.write( "\n" ); document.write( "* There is sufficient evidence at the 0.05 level of significance to conclude that there is an association between academic performance and self-esteem in the population of ten-year-old children.\r \n" ); document.write( "\n" ); document.write( "**Note:**\r \n" ); document.write( "\n" ); document.write( "* This analysis assumes that the expected frequencies in each cell are greater than 5. \n" ); document.write( "* You can use statistical software (like R or SPSS) to perform the chi-square test for independence more easily and accurately.\r \n" ); document.write( "\n" ); document.write( "This analysis provides a basic framework for conducting a chi-square test for independence. \n" ); document.write( " \n" ); document.write( " |