document.write( "Question 1209340: Tony is three times as old as Gloria. Six years ago, Tony was five times as old as Gloria. Find the present ages of Tony and Gloria.\r
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Algebra.Com's Answer #848516 by ikleyn(52788) $\"\"$ $\"About$

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\n" ); document.write( "Tony is three times as old as Gloria. Six years ago, Tony was five times as old as Gloria.
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document.write( "Let Tony's age be x years;\r\n" );
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document.write( "Then Gloria 's age is 3x years, according to the problem.\r\n" );
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document.write( "Six years ago, Tony   was (x-6) years old    (1)\r\n" );
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document.write( "               Gloria was 3x-6 years ago.    (2)\r\n" );
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document.write( "We equate 5 times value of (1) and value of (2)\r\n" );
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document.write( "    5(x-6) = 3x - 6.\r\n" );
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document.write( "This is your setup equation.  Simplify and find x\r\n" );
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document.write( "    5x - 30 = 3x - 6\r\n" );
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document.write( "    5x - 3x = 30 - 6\r\n" );
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document.write( "       2x   =   24\r\n" );
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document.write( "        x   =   24/2 = 12.\r\n" );
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document.write( "ANSWER.  Tony is 12 years old.  Gloria is 3x = 3*12 = 36 years old.\r\n" );
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document.write( "CHECK.  6 years ago their ages were 6 and 30 years, with the ratio  30/6 = 5.   ! correct !\r\n" );
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