document.write( "Question 1195038: Find random variable X+2Y and Y median, dispersion and correlation coefficient, if X and Y are independent variables, X~P(4)(Poisson variable) and Y~T(1, 6)(continuous distribution) \n" ); document.write( "
Algebra.Com's Answer #848501 by proyaop(69)\"\" \"About 
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Certainly, let's analyze the random variable X + 2Y and find the requested statistics.\r
\n" ); document.write( "\n" ); document.write( "**1. Define the Distributions**\r
\n" ); document.write( "\n" ); document.write( "* **X:** Poisson distribution with mean (λ) = 4.
\n" ); document.write( " * Probability Mass Function (PMF): P(X = k) = (e^(-λ) * λ^k) / k!
\n" ); document.write( "* **Y:** Continuous uniform distribution over the interval [1, 6].
\n" ); document.write( " * Probability Density Function (PDF): f(y) = 1/5 for 1 ≤ y ≤ 6, and 0 otherwise.\r
\n" ); document.write( "\n" ); document.write( "**2. X + 2Y**\r
\n" ); document.write( "\n" ); document.write( "* Since X and Y are independent, the distribution of X + 2Y will not have a simple closed-form expression.
\n" ); document.write( "* However, we can simulate values of X and Y and then calculate values of X + 2Y to analyze its properties.\r
\n" ); document.write( "\n" ); document.write( "**3. Median, Dispersion, and Correlation Coefficient of Y**\r
\n" ); document.write( "\n" ); document.write( "* **Median of Y:**
\n" ); document.write( " * For a continuous uniform distribution, the median is the midpoint of the interval: (1 + 6) / 2 = 3.5\r
\n" ); document.write( "\n" ); document.write( "* **Dispersion of Y (Standard Deviation):**
\n" ); document.write( " * For a continuous uniform distribution over the interval [a, b], the standard deviation is:
\n" ); document.write( " * σ_Y = (b - a) / √12 = (6 - 1) / √12 ≈ 1.44\r
\n" ); document.write( "\n" ); document.write( "* **Correlation Coefficient between X and Y:**
\n" ); document.write( " * Since X and Y are independent, their correlation coefficient is 0.\r
\n" ); document.write( "\n" ); document.write( "**Simulation in Python**\r
\n" ); document.write( "\n" ); document.write( "```python
\n" ); document.write( "import numpy as np
\n" ); document.write( "from scipy.stats import poisson, uniform\r
\n" ); document.write( "\n" ); document.write( "# Define the distributions of X and Y
\n" ); document.write( "X = poisson.rvs(mu=4, size=10000) # Poisson distribution with mean 4
\n" ); document.write( "Y = uniform.rvs(loc=1, scale=5, size=10000) # Uniform distribution between 1 and 6\r
\n" ); document.write( "\n" ); document.write( "# Create the new random variable Z = X + 2Y
\n" ); document.write( "Z = X + 2*Y\r
\n" ); document.write( "\n" ); document.write( "# Calculate the median of Y
\n" ); document.write( "median_y = np.median(Y)\r
\n" ); document.write( "\n" ); document.write( "# Calculate the dispersion of Y (standard deviation)
\n" ); document.write( "dispersion_y = np.std(Y)\r
\n" ); document.write( "\n" ); document.write( "# Since X and Y are independent, their correlation coefficient is 0
\n" ); document.write( "correlation_coefficient = 0\r
\n" ); document.write( "\n" ); document.write( "# Print the results
\n" ); document.write( "print(f\"Median of Y: {median_y}\")
\n" ); document.write( "print(f\"Dispersion of Y (Standard Deviation): {dispersion_y}\")
\n" ); document.write( "print(f\"Correlation Coefficient between X and Y: {correlation_coefficient}\")
\n" ); document.write( "```\r
\n" ); document.write( "\n" ); document.write( "This code will generate a large number of samples from the distributions of X and Y, and then calculate the median, dispersion, and correlation coefficient of Y. \r
\n" ); document.write( "\n" ); document.write( "**Key Points:**\r
\n" ); document.write( "\n" ); document.write( "* The distribution of X + 2Y will be more complex than either X or Y individually due to the combination of a discrete (Poisson) and continuous (uniform) distribution.
\n" ); document.write( "* The median of Y for a uniform distribution is easily calculated as the midpoint of the interval.
\n" ); document.write( "* The independence of X and Y ensures a correlation coefficient of 0.\r
\n" ); document.write( "\n" ); document.write( "I hope this explanation is helpful! Let me know if you have any further questions.
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