document.write( "Question 1197733: A dentist is interested in the proportion of adults who have had their wisdom teeth removed. To determine this, a random sample of {227} adults was collected and it was found that {105} still had their wisdom teeth. \r
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document.write( "Using this information construct an approximate 90% confidence interval for the proportion of adults who have had their wisdom teeth removed. \n" );
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Algebra.Com's Answer #848489 by proyaop(69)![]() ![]() ![]() You can put this solution on YOUR website! **1. Calculate the Sample Proportion (p̂)**\r \n" ); document.write( "\n" ); document.write( "* p̂ = (Number of adults who have had wisdom teeth removed) / (Sample size) \n" ); document.write( "* p̂ = (227 - 105) / 227 \n" ); document.write( "* p̂ = 122 / 227 \n" ); document.write( "* p̂ ≈ 0.537 \r \n" ); document.write( "\n" ); document.write( "**2. Find the Critical Value (z*)**\r \n" ); document.write( "\n" ); document.write( "* For a 90% confidence interval, the critical value (z*) is 1.645. This value corresponds to the z-score that captures 90% of the data within two standard deviations of the mean in a standard normal distribution.\r \n" ); document.write( "\n" ); document.write( "**3. Calculate the Standard Error**\r \n" ); document.write( "\n" ); document.write( "* Standard Error (SE) = √(p̂ * (1 - p̂) / n) \n" ); document.write( " * where: \n" ); document.write( " * p̂ = sample proportion (0.537) \n" ); document.write( " * n = sample size (227)\r \n" ); document.write( "\n" ); document.write( "* SE = √(0.537 * (1 - 0.537) / 227) \n" ); document.write( "* SE ≈ 0.033\r \n" ); document.write( "\n" ); document.write( "**4. Calculate the Margin of Error**\r \n" ); document.write( "\n" ); document.write( "* Margin of Error (ME) = z* * SE \n" ); document.write( "* ME = 1.645 * 0.033 \n" ); document.write( "* ME ≈ 0.054\r \n" ); document.write( "\n" ); document.write( "**5. Construct the Confidence Interval**\r \n" ); document.write( "\n" ); document.write( "* Lower Limit = p̂ - ME = 0.537 - 0.054 = 0.483 \n" ); document.write( "* Upper Limit = p̂ + ME = 0.537 + 0.054 = 0.591\r \n" ); document.write( "\n" ); document.write( "**Therefore, the 90% confidence interval for the proportion of adults who have had their wisdom teeth removed is (0.483, 0.591).**\r \n" ); document.write( "\n" ); document.write( "**Interpretation:**\r \n" ); document.write( "\n" ); document.write( "We are 90% confident that the true proportion of adults who have had their wisdom teeth removed lies between 48.3% and 59.1%. \n" ); document.write( " \n" ); document.write( " |