document.write( "Question 1194224: 8.34 Working Women In an Advertising Age
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document.write( "white paper concerning the changing role of women as
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document.write( "“breadwinners” in the American family, it was
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document.write( "reported that according to their survey with JWT,
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document.write( "working men reported doing 54 minutes of household
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document.write( "chores a day, while working women reported tackling
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document.write( "72 minutes daily. But when examined more closely,
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document.write( "Millennial men reported doing just as many household
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document.write( "chores as the average working women, 72 minutes,
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document.write( "compared to an average of 54 minutes among both
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document.write( "Boomer men and Xer men.6 The information that follows is adapted from these data and is based on random samples of 1136 men and 795 women.
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document.write( "Standard
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document.write( "Mean Deviation n
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document.write( "All Women 72 10.4 795
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document.write( "All Men 54 12.7 1136
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document.write( "Millennial 72 9.2 345
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document.write( "Boomers 54 13.9 475
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document.write( "Xers 54 10.5 316
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document.write( "a. Construct a 95% confidence interval for the average
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document.write( "time all men spend doing household chores.
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document.write( "b. Construct a 95% confidence interval for the average
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document.write( "time women spend doing household chores \n" );
document.write( "
Algebra.Com's Answer #848464 by proyaop(69)![]() ![]() ![]() You can put this solution on YOUR website! **a. Construct a 95% Confidence Interval for the Average Time All Men Spend Doing Household Chores**\r \n" ); document.write( "\n" ); document.write( "* **Given:** \n" ); document.write( " * Sample Mean (x̄) = 54 minutes \n" ); document.write( " * Sample Standard Deviation (s) = 12.7 minutes \n" ); document.write( " * Sample Size (n) = 1136 men \n" ); document.write( " * Confidence Level = 95% \r \n" ); document.write( "\n" ); document.write( "* **Find the Critical Value (zα/2):** \n" ); document.write( " * For a 95% confidence level, α = 0.05 \n" ); document.write( " * zα/2 = 1.96 (from the standard normal distribution table)\r \n" ); document.write( "\n" ); document.write( "* **Calculate the Standard Error of the Mean (SEM):** \n" ); document.write( " * SEM = s / √n \n" ); document.write( " * SEM = 12.7 / √1136 \n" ); document.write( " * SEM ≈ 0.377\r \n" ); document.write( "\n" ); document.write( "* **Calculate the Margin of Error (ME):** \n" ); document.write( " * ME = zα/2 * SEM \n" ); document.write( " * ME = 1.96 * 0.377 \n" ); document.write( " * ME ≈ 0.739\r \n" ); document.write( "\n" ); document.write( "* **Construct the Confidence Interval:** \n" ); document.write( " * Lower Limit = x̄ - ME = 54 - 0.739 = 53.261 minutes \n" ); document.write( " * Upper Limit = x̄ + ME = 54 + 0.739 = 54.739 minutes\r \n" ); document.write( "\n" ); document.write( "* **95% Confidence Interval for All Men:** (53.261 minutes, 54.739 minutes)\r \n" ); document.write( "\n" ); document.write( "**b. Construct a 95% Confidence Interval for the Average Time Women Spend Doing Household Chores**\r \n" ); document.write( "\n" ); document.write( "* **Given:** \n" ); document.write( " * Sample Mean (x̄) = 72 minutes \n" ); document.write( " * Sample Standard Deviation (s) = 10.4 minutes \n" ); document.write( " * Sample Size (n) = 795 women \n" ); document.write( " * Confidence Level = 95% \r \n" ); document.write( "\n" ); document.write( "* **Find the Critical Value (zα/2):** \n" ); document.write( " * Same as part (a): zα/2 = 1.96\r \n" ); document.write( "\n" ); document.write( "* **Calculate the Standard Error of the Mean (SEM):** \n" ); document.write( " * SEM = s / √n \n" ); document.write( " * SEM = 10.4 / √795 \n" ); document.write( " * SEM ≈ 0.368\r \n" ); document.write( "\n" ); document.write( "* **Calculate the Margin of Error (ME):** \n" ); document.write( " * ME = zα/2 * SEM \n" ); document.write( " * ME = 1.96 * 0.368 \n" ); document.write( " * ME ≈ 0.721\r \n" ); document.write( "\n" ); document.write( "* **Construct the Confidence Interval:** \n" ); document.write( " * Lower Limit = x̄ - ME = 72 - 0.721 = 71.279 minutes \n" ); document.write( " * Upper Limit = x̄ + ME = 72 + 0.721 = 72.721 minutes\r \n" ); document.write( "\n" ); document.write( "* **95% Confidence Interval for All Women:** (71.279 minutes, 72.721 minutes)\r \n" ); document.write( "\n" ); document.write( "**Interpretation:**\r \n" ); document.write( "\n" ); document.write( "* We are 95% confident that the true average time all men spend on household chores lies between 53.261 and 54.739 minutes. \n" ); document.write( "* We are 95% confident that the true average time all women spend on household chores lies between 71.279 and 72.721 minutes. \n" ); document.write( " \n" ); document.write( " |