document.write( "Question 1194896: Please help with the homework:
\n" ); document.write( "Calculate the sum accrued on a fixed deposit of R10000 is invested on 15 march 2021 until 1 July 2023, if interest is credited annually on the 1 July at 15,5%.
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Algebra.Com's Answer #848443 by ElectricPavlov(122)\"\" \"About 
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To calculate the accrued amount on a fixed deposit of R10,000 invested from 15 March 2021 to 1 July 2023, with interest credited annually on 1 July at an annual rate of 15.5%, follow these steps:\r
\n" ); document.write( "\n" ); document.write( "**1. Determine the Investment Period:**\r
\n" ); document.write( "\n" ); document.write( "- **Start Date:** 15 March 2021
\n" ); document.write( "- **End Date:** 1 July 2023\r
\n" ); document.write( "\n" ); document.write( "**2. Calculate the Total Investment Duration:**\r
\n" ); document.write( "\n" ); document.write( "- **From 15 March 2021 to 1 July 2023:**\r
\n" ); document.write( "\n" ); document.write( " - **Year 1:** 15 March 2021 to 1 July 2021
\n" ); document.write( " - **Days:** 15 March to 31 March (17 days) + April (30 days) + May (31 days) + June (30 days) + 1 July (1 day) = 109 days\r
\n" ); document.write( "\n" ); document.write( " - **Year 2:** 1 July 2021 to 1 July 2022
\n" ); document.write( " - **Days:** 365 days (non-leap year)\r
\n" ); document.write( "\n" ); document.write( " - **Year 3:** 1 July 2022 to 1 July 2023
\n" ); document.write( " - **Days:** 365 days\r
\n" ); document.write( "\n" ); document.write( " - **Total Days:** 109 + 365 + 365 = 839 days\r
\n" ); document.write( "\n" ); document.write( " - **Total Years:** 839 days ÷ 365 days/year ≈ 2.2986 years\r
\n" ); document.write( "\n" ); document.write( "**3. Apply the Compound Interest Formula:**\r
\n" ); document.write( "\n" ); document.write( "The compound interest formula is:\r
\n" ); document.write( "\n" ); document.write( "\[ A = P \times (1 + r)^t \]\r
\n" ); document.write( "\n" ); document.write( "Where:
\n" ); document.write( "- \( A \) = Accrued amount
\n" ); document.write( "- \( P \) = Principal amount (R10,000)
\n" ); document.write( "- \( r \) = Annual interest rate (15.5% or 0.155)
\n" ); document.write( "- \( t \) = Time in years (2.2986)\r
\n" ); document.write( "\n" ); document.write( "**4. Perform the Calculation:**\r
\n" ); document.write( "\n" ); document.write( "\[ A = 10,\!000 \times (1 + 0.155)^{2.2986} \]\r
\n" ); document.write( "\n" ); document.write( "First, calculate \( (1 + 0.155) \):\r
\n" ); document.write( "\n" ); document.write( "\[ 1 + 0.155 = 1.155 \]\r
\n" ); document.write( "\n" ); document.write( "Next, raise 1.155 to the power of 2.2986. Using a calculator:\r
\n" ); document.write( "\n" ); document.write( "\[ 1.155^{2.2986} \approx 1.404 \]\r
\n" ); document.write( "\n" ); document.write( "Now, multiply by the principal:\r
\n" ); document.write( "\n" ); document.write( "\[ A = 10,\!000 \times 1.404 = 14,\!040 \]\r
\n" ); document.write( "\n" ); document.write( "**5. Conclusion:**\r
\n" ); document.write( "\n" ); document.write( "The accrued amount on the fixed deposit of R10,000, invested from 15 March 2021 to 1 July 2023 at an annual interest rate of 15.5%, is approximately **R14,040**.
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