document.write( "Question 1194885: A manufacturer of automobile transmissions uses two different processes. Management ordered a study of the production costs to see if there is a difference between the two processes. A summary of the findings is shown next.\r
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document.write( "Process 1 Process 2 Total Process totals ($100s) 137 108 245\r
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document.write( "Sample size 10 10 20\r
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document.write( "Sum of squares 1,893 1,188 3,081\r
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document.write( "a. What is the critical value of F at the 5% level of significance?\r
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document.write( "b. State the null hypothesis and the alternate hypothesis\r
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document.write( "c. State the decision rule\r
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document.write( "d. Compute the value of the test statistic\r
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document.write( "e. What is your decision regarding H0 \r
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document.write( "f. Interpret the result \n" );
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Algebra.Com's Answer #848440 by ElectricPavlov(122)![]() ![]() ![]() You can put this solution on YOUR website! **a) Critical Value of F at the 5% level of significance**\r \n" ); document.write( "\n" ); document.write( "* **Degrees of Freedom:** \n" ); document.write( " * Between groups (df1): k - 1 = 2 groups - 1 = 1 \n" ); document.write( " * Within groups (df2): N - k = 20 - 2 = 18\r \n" ); document.write( "\n" ); document.write( "* **F-distribution table:** \n" ); document.write( " * Look up the F-critical value in an F-distribution table with df1 = 1 and df2 = 18, and α = 0.05. \n" ); document.write( " * **F-critical ≈ 4.41**\r \n" ); document.write( "\n" ); document.write( "**b) Null and Alternative Hypotheses**\r \n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H0):** \n" ); document.write( " * μ1 = μ2 \n" ); document.write( " * There is no significant difference in the mean production costs between the two processes.\r \n" ); document.write( "\n" ); document.write( "* **Alternative Hypothesis (H1):** \n" ); document.write( " * μ1 ≠ μ2 \n" ); document.write( " * There is a significant difference in the mean production costs between the two processes.\r \n" ); document.write( "\n" ); document.write( "**c) Decision Rule**\r \n" ); document.write( "\n" ); document.write( "* **Reject H0 if the calculated F-statistic is greater than the critical F-value (F > 4.41).** \n" ); document.write( "* **Fail to reject H0 if the calculated F-statistic is less than or equal to the critical F-value (F ≤ 4.41).**\r \n" ); document.write( "\n" ); document.write( "**d) Compute the Value of the Test Statistic**\r \n" ); document.write( "\n" ); document.write( "1. **Calculate Mean Squares:** \n" ); document.write( " * **Between Groups Sum of Squares (SSB):** \n" ); document.write( " * SSB = [Σ(n_i * (X̄_i - X̄)²)] / (k - 1) \n" ); document.write( " * where: \n" ); document.write( " * n_i: sample size of group i \n" ); document.write( " * X̄_i: mean of group i \n" ); document.write( " * X̄: overall mean \n" ); document.write( " * k: number of groups\r \n" ); document.write( "\n" ); document.write( " * X̄_1 (Process 1) = 137 / 10 = 13.7 \n" ); document.write( " * X̄_2 (Process 2) = 108 / 10 = 10.8 \n" ); document.write( " * X̄ (Overall) = 245 / 20 = 12.25\r \n" ); document.write( "\n" ); document.write( " * SSB = [(10 * (13.7 - 12.25)²) + (10 * (10.8 - 12.25)²)] / (2 - 1) \n" ); document.write( " * SSB = 198.05\r \n" ); document.write( "\n" ); document.write( " * **Within Groups Sum of Squares (SSW):** \n" ); document.write( " * SSW = Total Sum of Squares (SST) - Between Groups Sum of Squares (SSB) \n" ); document.write( " * SSW = 3081 - 198.05 = 2882.95\r \n" ); document.write( "\n" ); document.write( " * **Mean Square Between Groups (MSB):** \n" ); document.write( " * MSB = SSB / (k - 1) = 198.05 / 1 = 198.05\r \n" ); document.write( "\n" ); document.write( " * **Mean Square Within Groups (MSW):** \n" ); document.write( " * MSW = SSW / (N - k) = 2882.95 / 18 = 160.16\r \n" ); document.write( "\n" ); document.write( "2. **Calculate F-statistic:** \n" ); document.write( " * F = MSB / MSW = 198.05 / 160.16 = 1.236\r \n" ); document.write( "\n" ); document.write( "**e) Decision**\r \n" ); document.write( "\n" ); document.write( "* Since the calculated F-statistic (1.236) is less than the critical F-value (4.41), we **fail to reject the null hypothesis (H0)**.\r \n" ); document.write( "\n" ); document.write( "**f) Interpretation**\r \n" ); document.write( "\n" ); document.write( "* There is **not** enough evidence at the 5% level of significance to conclude that there is a significant difference in the mean production costs between the two processes.\r \n" ); document.write( "\n" ); document.write( "**In summary:**\r \n" ); document.write( "\n" ); document.write( "* The analysis suggests that there is no significant difference in the mean production costs between the two processes. \n" ); document.write( " \n" ); document.write( " |