document.write( "Question 1196639: A relief organization must track their supply and demand for various blood types. They estimate that about 46% of the population in a country has Type O blood, 42% Type A, 9% Type B, and the rest Type AB. \r
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document.write( "a) If someone volunteers to give blood, what is the probability that this donor: i) Has Type AB blood? ii) Has Type A or Type B blood? iii) Is not Type O?
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document.write( "b) Among four potential donors, what is the probability that: i) All are Type O? ii) None have Type AB blood? iii) Not all are Type A? iv) At least one person is Type B? \n" );
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Algebra.Com's Answer #848411 by ElectricPavlov(122)![]() ![]() ![]() You can put this solution on YOUR website! **a) Probabilities for a Single Donor**\r \n" ); document.write( "\n" ); document.write( "* **i) Has Type AB blood:** \n" ); document.write( " * Probability = 100% - (46% + 42% + 9%) = 3%\r \n" ); document.write( "\n" ); document.write( "* **ii) Has Type A or Type B blood:** \n" ); document.write( " * Probability = 42% + 9% = 51%\r \n" ); document.write( "\n" ); document.write( "* **iii) Is not Type O blood:** \n" ); document.write( " * Probability = 100% - 46% = 54%\r \n" ); document.write( "\n" ); document.write( "**b) Probabilities for Four Donors**\r \n" ); document.write( "\n" ); document.write( "* **i) All are Type O:** \n" ); document.write( " * Probability = (0.46) * (0.46) * (0.46) * (0.46) = 0.46^4 ≈ 0.0457 (or 4.57%)\r \n" ); document.write( "\n" ); document.write( "* **ii) None have Type AB blood:** \n" ); document.write( " * Probability of not having Type AB = 100% - 3% = 97% \n" ); document.write( " * Probability that none have Type AB = (0.97) * (0.97) * (0.97) * (0.97) = 0.97^4 ≈ 0.8853 (or 88.53%)\r \n" ); document.write( "\n" ); document.write( "* **iii) Not all are Type A:** \n" ); document.write( " * Probability that all are Type A = (0.42) * (0.42) * (0.42) * (0.42) = 0.42^4 ≈ 0.0311 (or 3.11%) \n" ); document.write( " * Probability that not all are Type A = 100% - 3.11% = 96.89%\r \n" ); document.write( "\n" ); document.write( "* **iv) At least one person is Type B:** \n" ); document.write( " * Probability that none are Type B = (1 - 0.09)^4 = 0.6860 \n" ); document.write( " * Probability that at least one person is Type B = 100% - 68.60% = 31.40%\r \n" ); document.write( "\n" ); document.write( "**Note:** These calculations assume that the blood types of the donors are independent of each other. \n" ); document.write( " \n" ); document.write( " |