document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=116631>Question 116631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "The formula below can be used to find the number of milligrams D of a certain drug that is in a patients bloodstream h hours after the drug has been administered. <BR>\n" );
document.write( "D = 5e^(-0.37h) <BR>\n" );
document.write( "When the number of milligrams reaches 2, the drug is to be administered again. What is the time between injections?<BR>\n" );
document.write( " hours\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #84837 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=84837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> setting D equal to 2 and dividing by 5 gives .4=e^(-0.37h)\r<BR>\n" );
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document.write( "taking the natural log gives ln(.4)=-0.37h ___ dividing by -0.37 gives (ln(.4))/(-0.37)=h </SPAN>\n" );
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