document.write( "Question 116672: Ok, I am in 7th grade pre-algebra but whenever my teacher talks I don't understand half of what he is saying. I have looked on numerous web pages, and I came across this one. My question is:
\n" ); document.write( "3x (divided by) 2-2=7 This may seem easy but I have no idea what to do. Please help as much as you can. Thank you anyway!
\n" ); document.write( "~Student
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Algebra.Com's Answer #84835 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"3x%2F2-2=7\"...........\"3x%2F2\" we can write like \"%283%2F2%29x\"
\n" ); document.write( "\"%283%2F2%29x-2=7\"...........since you have a fraction \"3x%2F2\" on the left, first what you need is to eliminate denominator \"2\"\r
\n" ); document.write( "\n" ); document.write( "You can do it if you multiply by \"2\" all terms on both sides of equal sign.\r
\n" ); document.write( "\n" ); document.write( "\"2%283%2F2%29x+-+2%2A2+=+7%2A2\"............we can write this as:\r
\n" ); document.write( "\n" ); document.write( "\"3x%282%2F2%29+-+2%2A2+=+7%2A2\"\r
\n" ); document.write( "\n" ); document.write( "\"3x+-+4+=+14\".......move \"-4\" to the right; doing it, it will change a sign\r
\n" ); document.write( "\n" ); document.write( "\"3x++=+14+%2B+4\"\r
\n" ); document.write( "\n" ); document.write( "\"3x++=+18\"......now divide both sides by \"3\" in order to have \"1x\"\r
\n" ); document.write( "\n" ); document.write( "\"3x%2F3+=+18%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+6\"\r
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\n" ); document.write( "\n" ); document.write( "you can check your result if you plug in \"x=6\" in:\r
\n" ); document.write( "\n" ); document.write( "\"3x%2F2-2=7\"...........\r
\n" ); document.write( "\n" ); document.write( "\"%283%2A6%29%2F2+-+2+=+7\"\r
\n" ); document.write( "\n" ); document.write( "\"18%2F2+-+2+=+7\"\r
\n" ); document.write( "\n" ); document.write( "\"9+-+2+=+7\"
\n" ); document.write( "\"7+=+7\"..... since left side of equal sign is same as the right side, it means \"x=6\" is your solution\r
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