document.write( "Question 1198081: The following table shows the average life expectancies in several countries. Assume that all premiums you calculate are based on end-of-month deposits in a fund yielding 6.8% annual interest compounded monthly to be paid out when a person reaches the life expectancy. HINT [See Example 2.]
\n" ); document.write( "Country Japan Canada U.K. U.S. Mexico China India
\n" ); document.write( "Life
\n" ); document.write( "Expectancy:
\n" ); document.write( "Male 80 80 79 76 73 74 64
\n" ); document.write( "Life
\n" ); document.write( "Expectancy:
\n" ); document.write( "Female 87 84 83 81 79 77 68
\n" ); document.write( "Calculate the life insurance monthly premium that a 50-year-old female in Japan would pay for a $10,000,000 policy. (Round your answer to the nearest cent.)
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Algebra.Com's Answer #848346 by onyulee(41)\"\" \"About 
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**1. Determine the Number of Months**\r
\n" ); document.write( "\n" ); document.write( "* Life expectancy for a 50-year-old female in Japan: 87 years
\n" ); document.write( "* Years to live: 87 years - 50 years = 37 years
\n" ); document.write( "* Number of months to live: 37 years * 12 months/year = 444 months\r
\n" ); document.write( "\n" ); document.write( "**2. Calculate the Monthly Interest Rate**\r
\n" ); document.write( "\n" ); document.write( "* Annual interest rate: 6.8%
\n" ); document.write( "* Monthly interest rate: 6.8% / 12 = 0.5667%\r
\n" ); document.write( "\n" ); document.write( "**3. Calculate the Future Value of a Single Deposit**\r
\n" ); document.write( "\n" ); document.write( "* We need to find the future value of a single deposit that will grow to $10,000,000 in 444 months.
\n" ); document.write( "* Use the future value of an ordinary annuity formula:\r
\n" ); document.write( "\n" ); document.write( " * FV = P * [(1 + r)^n - 1] / r \r
\n" ); document.write( "\n" ); document.write( " * Where:
\n" ); document.write( " * FV = Future Value ($10,000,000)
\n" ); document.write( " * P = Monthly Premium (unknown)
\n" ); document.write( " * r = Monthly interest rate (0.005667)
\n" ); document.write( " * n = Number of months (444)\r
\n" ); document.write( "\n" ); document.write( "**4. Solve for the Monthly Premium (P)**\r
\n" ); document.write( "\n" ); document.write( "* Rearrange the formula to solve for P:\r
\n" ); document.write( "\n" ); document.write( " * P = FV * [r / ((1 + r)^n - 1)]\r
\n" ); document.write( "\n" ); document.write( "* Substitute the values:\r
\n" ); document.write( "\n" ); document.write( " * P = $10,000,000 * [0.005667 / ((1 + 0.005667)^444 - 1)]\r
\n" ); document.write( "\n" ); document.write( "* Calculate P:\r
\n" ); document.write( "\n" ); document.write( " * P ≈ $10,000,000 * [0.005667 / (15.236 - 1)]
\n" ); document.write( " * P ≈ $10,000,000 * [0.005667 / 14.236]
\n" ); document.write( " * P ≈ $10,000,000 * 0.000398
\n" ); document.write( " * P ≈ $3,980\r
\n" ); document.write( "\n" ); document.write( "**Therefore, the monthly premium for a 50-year-old female in Japan for a $10,000,000 life insurance policy would be approximately $3,980.**\r
\n" ); document.write( "\n" ); document.write( "**Note:**\r
\n" ); document.write( "\n" ); document.write( "* This calculation assumes that the interest rate remains constant over the entire 37-year period, which may not be the case in reality.
\n" ); document.write( "* This calculation also assumes that the individual lives exactly to the life expectancy.
\n" ); document.write( "* This is a simplified model and actual life insurance premiums are determined by various factors, including health, lifestyle, and other risk factors.\r
\n" ); document.write( "\n" ); document.write( "This information is for illustrative purposes only and does not constitute financial advice. Please consult with a qualified financial advisor for personalized guidance.
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