document.write( "Question 1198081: The following table shows the average life expectancies in several countries. Assume that all premiums you calculate are based on end-of-month deposits in a fund yielding 6.8% annual interest compounded monthly to be paid out when a person reaches the life expectancy. HINT [See Example 2.]
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document.write( "Country Japan Canada U.K. U.S. Mexico China India
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document.write( "Life
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document.write( "Expectancy:
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document.write( "Male 80 80 79 76 73 74 64
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document.write( "Life
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document.write( "Expectancy:
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document.write( "Female 87 84 83 81 79 77 68
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document.write( "Calculate the life insurance monthly premium that a 50-year-old female in Japan would pay for a $10,000,000 policy. (Round your answer to the nearest cent.) \n" );
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Algebra.Com's Answer #848346 by onyulee(41)![]() ![]() ![]() You can put this solution on YOUR website! **1. Determine the Number of Months**\r \n" ); document.write( "\n" ); document.write( "* Life expectancy for a 50-year-old female in Japan: 87 years \n" ); document.write( "* Years to live: 87 years - 50 years = 37 years \n" ); document.write( "* Number of months to live: 37 years * 12 months/year = 444 months\r \n" ); document.write( "\n" ); document.write( "**2. Calculate the Monthly Interest Rate**\r \n" ); document.write( "\n" ); document.write( "* Annual interest rate: 6.8% \n" ); document.write( "* Monthly interest rate: 6.8% / 12 = 0.5667%\r \n" ); document.write( "\n" ); document.write( "**3. Calculate the Future Value of a Single Deposit**\r \n" ); document.write( "\n" ); document.write( "* We need to find the future value of a single deposit that will grow to $10,000,000 in 444 months. \n" ); document.write( "* Use the future value of an ordinary annuity formula:\r \n" ); document.write( "\n" ); document.write( " * FV = P * [(1 + r)^n - 1] / r \r \n" ); document.write( "\n" ); document.write( " * Where: \n" ); document.write( " * FV = Future Value ($10,000,000) \n" ); document.write( " * P = Monthly Premium (unknown) \n" ); document.write( " * r = Monthly interest rate (0.005667) \n" ); document.write( " * n = Number of months (444)\r \n" ); document.write( "\n" ); document.write( "**4. Solve for the Monthly Premium (P)**\r \n" ); document.write( "\n" ); document.write( "* Rearrange the formula to solve for P:\r \n" ); document.write( "\n" ); document.write( " * P = FV * [r / ((1 + r)^n - 1)]\r \n" ); document.write( "\n" ); document.write( "* Substitute the values:\r \n" ); document.write( "\n" ); document.write( " * P = $10,000,000 * [0.005667 / ((1 + 0.005667)^444 - 1)]\r \n" ); document.write( "\n" ); document.write( "* Calculate P:\r \n" ); document.write( "\n" ); document.write( " * P ≈ $10,000,000 * [0.005667 / (15.236 - 1)] \n" ); document.write( " * P ≈ $10,000,000 * [0.005667 / 14.236] \n" ); document.write( " * P ≈ $10,000,000 * 0.000398 \n" ); document.write( " * P ≈ $3,980\r \n" ); document.write( "\n" ); document.write( "**Therefore, the monthly premium for a 50-year-old female in Japan for a $10,000,000 life insurance policy would be approximately $3,980.**\r \n" ); document.write( "\n" ); document.write( "**Note:**\r \n" ); document.write( "\n" ); document.write( "* This calculation assumes that the interest rate remains constant over the entire 37-year period, which may not be the case in reality. \n" ); document.write( "* This calculation also assumes that the individual lives exactly to the life expectancy. \n" ); document.write( "* This is a simplified model and actual life insurance premiums are determined by various factors, including health, lifestyle, and other risk factors.\r \n" ); document.write( "\n" ); document.write( "This information is for illustrative purposes only and does not constitute financial advice. Please consult with a qualified financial advisor for personalized guidance. \n" ); document.write( " \n" ); document.write( " |