document.write( "Question 1198562: The bases of a frustum of a right circular cone are circles whose diameters are respectively 18 and 14 inches. With a slant height of 25 inches, the volume may be expressed as V = Χπ √γ in^3 where Χ and γ are integers. Find the smallest sum of Χ and γ. \n" ); document.write( "
Algebra.Com's Answer #848330 by onyulee(41)\"\" \"About 
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**1. Find the Radii**\r
\n" ); document.write( "\n" ); document.write( "* Radius of the larger base (R) = 18 inches / 2 = 9 inches
\n" ); document.write( "* Radius of the smaller base (r) = 14 inches / 2 = 7 inches\r
\n" ); document.write( "\n" ); document.write( "**2. Find the Height of the Frustum**\r
\n" ); document.write( "\n" ); document.write( "* Let 'h' be the height of the frustum.
\n" ); document.write( "* We have a right triangle formed by:
\n" ); document.write( " * Slant height (l) = 25 inches
\n" ); document.write( " * Height (h)
\n" ); document.write( " * Difference in radii (R - r) = 9 - 7 = 2 inches\r
\n" ); document.write( "\n" ); document.write( "* Using the Pythagorean Theorem:
\n" ); document.write( " * h² = l² - (R - r)²
\n" ); document.write( " * h² = 25² - 2²
\n" ); document.write( " * h² = 625 - 4
\n" ); document.write( " * h² = 621
\n" ); document.write( " * h = √621 inches\r
\n" ); document.write( "\n" ); document.write( "**3. Calculate the Volume of the Frustum**\r
\n" ); document.write( "\n" ); document.write( "* Volume (V) = (1/3) * π * h * (R² + Rr + r²)
\n" ); document.write( "* V = (1/3) * π * √621 * (9² + 9*7 + 7²)
\n" ); document.write( "* V = (1/3) * π * √621 * (81 + 63 + 49)
\n" ); document.write( "* V = (1/3) * π * √621 * 193\r
\n" ); document.write( "\n" ); document.write( "**4. Express the Volume in the Given Form**\r
\n" ); document.write( "\n" ); document.write( "* V = (193/3) * π * √621
\n" ); document.write( "* V = Χπ√γ \r
\n" ); document.write( "\n" ); document.write( "* **Χ = 193/3**
\n" ); document.write( "* **γ = 621**\r
\n" ); document.write( "\n" ); document.write( "**5. Find the Smallest Sum of Χ and γ**\r
\n" ); document.write( "\n" ); document.write( "* Sum = Χ + γ = (193/3) + 621
\n" ); document.write( "* Sum = 193/3 + 1863/3
\n" ); document.write( "* Sum = 2056/3 \r
\n" ); document.write( "\n" ); document.write( "**Therefore, the smallest sum of Χ and γ is 2056/3.**
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