document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198257>Question 1198257</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many inches long is the altitude of a regular triangular pyramid the base is 12 inches on a side and its volume is 103.8 cubic inches. Round off the answer to the nearest integer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #848327 by </B><A HREF=/tutors/aboutme.mpl?userid=onyulee><B>onyulee(41)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=onyulee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=848327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> **1. Find the Area of the Base**\r<BR>\n" );
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document.write( "* The base is an equilateral triangle with side length 12 inches.<BR>\n" );
document.write( "* Area of an equilateral triangle = (√3/4) * side² <BR>\n" );
document.write( "* Area of the base = (√3/4) * 12² = 36√3 square inches\r<BR>\n" );
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document.write( "**2. Use the Volume Formula**\r<BR>\n" );
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document.write( "* Volume of a pyramid = (1/3) * Base Area * Height<BR>\n" );
document.write( "* 103.8 = (1/3) * 36√3 * Height<BR>\n" );
document.write( "* Height = (103.8 * 3) / (36√3)<BR>\n" );
document.write( "* Height ≈ 5 inches\r<BR>\n" );
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document.write( "**Therefore, the altitude of the regular triangular pyramid is approximately 5 inches.**<BR>\n" );
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