document.write( "Question 1198291: Approximately 10.3% of
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document.write( "American high school students drop out of school before
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document.write( "graduation. Choose 10 students entering high school at
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document.write( "random. Find the probability that
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document.write( "a. No more than two drop out
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document.write( "b. At least 6 graduate
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document.write( "c. All 10 stay in school and graduate \n" );
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Algebra.Com's Answer #848320 by CPhill(1987) You can put this solution on YOUR website! **a) Probability that no more than two drop out**\r \n" ); document.write( "\n" ); document.write( "* This means we need to find the probability that 0, 1, or 2 students drop out.\r \n" ); document.write( "\n" ); document.write( "* We can use the binomial probability formula: \n" ); document.write( " P(X = k) = (nCk) * (p^k) * ((1-p)^(n-k)) \n" ); document.write( " where: \n" ); document.write( " * n = number of trials (10 students) \n" ); document.write( " * k = number of successes (dropouts) \n" ); document.write( " * p = probability of success (dropout rate = 0.103) \n" ); document.write( " * (nCk) = n! / (k! * (n-k)!) \r \n" ); document.write( "\n" ); document.write( "* P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)\r \n" ); document.write( "\n" ); document.write( "* Calculate each probability and sum them: \n" ); document.write( " * P(X = 0) = (10C0) * (0.103)^0 * (0.897)^10 ≈ 0.3372 \n" ); document.write( " * P(X = 1) = (10C1) * (0.103)^1 * (0.897)^9 ≈ 0.3708 \n" ); document.write( " * P(X = 2) = (10C2) * (0.103)^2 * (0.897)^8 ≈ 0.2015\r \n" ); document.write( "\n" ); document.write( "* P(X ≤ 2) ≈ 0.3372 + 0.3708 + 0.2015 ≈ 0.9095\r \n" ); document.write( "\n" ); document.write( "**Therefore, the probability that no more than two students drop out is approximately 0.9095.**\r \n" ); document.write( "\n" ); document.write( "**b) Probability that at least 6 graduate**\r \n" ); document.write( "\n" ); document.write( "* This means the probability that 4 or fewer students drop out (since 10 - 4 = 6).\r \n" ); document.write( "\n" ); document.write( "* P(X ≤ 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)\r \n" ); document.write( "\n" ); document.write( "* Calculate each probability and sum them: \n" ); document.write( " * P(X = 3) = (10C3) * (0.103)^3 * (0.897)^7 ≈ 0.0574 \n" ); document.write( " * P(X = 4) = (10C4) * (0.103)^4 * (0.897)^6 ≈ 0.0118\r \n" ); document.write( "\n" ); document.write( "* P(X ≤ 4) ≈ 0.9095 + 0.0574 + 0.0118 ≈ 0.9787\r \n" ); document.write( "\n" ); document.write( "* P(at least 6 graduate) = 1 - P(X ≤ 4) = 1 - 0.9787 ≈ 0.0213\r \n" ); document.write( "\n" ); document.write( "**Therefore, the probability that at least 6 students graduate is approximately 0.0213.**\r \n" ); document.write( "\n" ); document.write( "**c) Probability that all 10 stay in school and graduate**\r \n" ); document.write( "\n" ); document.write( "* This means that 0 students drop out.\r \n" ); document.write( "\n" ); document.write( "* P(X = 0) = (10C0) * (0.103)^0 * (0.897)^10 ≈ 0.3372\r \n" ); document.write( "\n" ); document.write( "**Therefore, the probability that all 10 students stay in school and graduate is approximately 0.3372.** \n" ); document.write( " \n" ); document.write( " |