document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=17589>Question 17589</A>: <I><SPAN STYLE=\"word-break: break-all;\"> add using the least common denominator<BR>\n" );
document.write( "2/3 + 1/6= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8483 by </B><A HREF=/tutors/aboutme.mpl?userid=whisper><B>whisper(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=whisper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First we have to find the least common denominator of LCD.\r<BR>\n" );
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document.write( "First factor each denominator.\r<BR>\n" );
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document.write( "3 = 3<BR>\n" );
document.write( "6 = 2 x 3\r<BR>\n" );
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document.write( "The least common denominator is then 2 x 3 = 6.\r<BR>\n" );
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document.write( "2/3 + 1/6<BR>\n" );
document.write( "(2/3)2/2) + 1/6<BR>\n" );
document.write( "4/6 + 1/6<BR>\n" );
document.write( "5/6\r<BR>\n" );
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document.write( "Please don't hesitate to ask if you have further questions! </SPAN>\n" );
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