document.write( "Question 1199773: A simple random sample of size n=49 is obtained from a population with mean = 80 and standard deviation = 14. \r
\n" ); document.write( "\n" ); document.write( "a) Describe the sampling distribution of x̅.\r
\n" ); document.write( "\n" ); document.write( "b) What is P(x̅ > 83)?\r
\n" ); document.write( "\n" ); document.write( "c) What is P(x̅ ≤ 75.8)?\r
\n" ); document.write( "\n" ); document.write( "d) What is P(78.3 < x̅ < 85.1)?
\n" ); document.write( "

Algebra.Com's Answer #848265 by CPhill(1987)\"\" \"About 
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**a) Describe the sampling distribution of x̅**\r
\n" ); document.write( "\n" ); document.write( "* **Mean of the sampling distribution (μ):**
\n" ); document.write( " * μ = μ = 80
\n" ); document.write( " * The mean of the sampling distribution of the sample means is equal to the population mean.\r
\n" ); document.write( "\n" ); document.write( "* **Standard deviation of the sampling distribution (standard error):**
\n" ); document.write( " * σ = σ / √n = 14 / √49 = 14 / 7 = 2 \r
\n" ); document.write( "\n" ); document.write( "* **Shape of the sampling distribution:**
\n" ); document.write( " * Since the sample size (n = 49) is sufficiently large (n ≥ 30), according to the Central Limit Theorem, the sampling distribution of the sample mean (x̅) will be approximately normally distributed, regardless of the shape of the original population distribution.\r
\n" ); document.write( "\n" ); document.write( "**Therefore:**\r
\n" ); document.write( "\n" ); document.write( "* The sampling distribution of x̅ is approximately normally distributed with:
\n" ); document.write( " * Mean (μ) = 80
\n" ); document.write( " * Standard deviation (σ) = 2 \r
\n" ); document.write( "\n" ); document.write( "**b) P(x̅ > 83)**\r
\n" ); document.write( "\n" ); document.write( "1. **Standardize the value:**
\n" ); document.write( " * z = (x̅ - μ) / σ
\n" ); document.write( " * z = (83 - 80) / 2 = 1.5\r
\n" ); document.write( "\n" ); document.write( "2. **Find the probability using a standard normal distribution table or calculator:**
\n" ); document.write( " * P(x̅ > 83) = P(Z > 1.5)
\n" ); document.write( " * From the z-table, P(Z > 1.5) = 0.0668\r
\n" ); document.write( "\n" ); document.write( "**Therefore, P(x̅ > 83) = 0.0668**\r
\n" ); document.write( "\n" ); document.write( "**c) P(x̅ ≤ 75.8)**\r
\n" ); document.write( "\n" ); document.write( "1. **Standardize the value:**
\n" ); document.write( " * z = (75.8 - 80) / 2 = -2.1\r
\n" ); document.write( "\n" ); document.write( "2. **Find the probability using a standard normal distribution table or calculator:**
\n" ); document.write( " * P(x̅ ≤ 75.8) = P(Z ≤ -2.1)
\n" ); document.write( " * From the z-table, P(Z ≤ -2.1) = 0.0179\r
\n" ); document.write( "\n" ); document.write( "**Therefore, P(x̅ ≤ 75.8) = 0.0179**\r
\n" ); document.write( "\n" ); document.write( "**d) P(78.3 < x̅ < 85.1)**\r
\n" ); document.write( "\n" ); document.write( "1. **Standardize the values:**
\n" ); document.write( " * z1 = (78.3 - 80) / 2 = -0.85
\n" ); document.write( " * z2 = (85.1 - 80) / 2 = 2.55\r
\n" ); document.write( "\n" ); document.write( "2. **Find the probabilities using a standard normal distribution table or calculator:**
\n" ); document.write( " * P(x̅ < 85.1) = P(Z < 2.55)
\n" ); document.write( " * P(x̅ < 78.3) = P(Z < -0.85)\r
\n" ); document.write( "\n" ); document.write( "3. **Calculate the desired probability:**
\n" ); document.write( " * P(78.3 < x̅ < 85.1) = P(x̅ < 85.1) - P(x̅ < 78.3)
\n" ); document.write( " = P(Z < 2.55) - P(Z < -0.85)
\n" ); document.write( " ≈ 0.9946 - 0.1977
\n" ); document.write( " ≈ 0.7969\r
\n" ); document.write( "\n" ); document.write( "**Therefore, P(78.3 < x̅ < 85.1) = 0.7969**
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