document.write( "Question 1209314: In a bookshop, 40% of the stationery were pencils and the rest were erasers and rulers. The number of rulers is 1/4
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Algebra.Com's Answer #848261 by ikleyn(52914) $\"\"$ $\"About$

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\n" ); document.write( "In a bookshop, 40% of the stationery were pencils and the rest were erasers and rulers.
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\n" ); document.write( "(a) What percentage of the stationery were erasers?
\n" ); document.write( "(b) How many rulers were there?
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document.write( "Let the number of rulers be x.\r\n" );
document.write( "Then the number of erasers is 4x.\r\n" );
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document.write( "x + 4x = 5x is 60% of stationery;\r\n" );
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document.write( "hence, the number of pencils, which is 40% of stationery, is 2/3 of 5x,  or  .\r\n" );
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document.write( "The problem says that there were 120 more erasers than pencils.\r\n" );
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document.write( "    4x -  = 120.\r\n" );
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document.write( "To solve it, multiply all the terms by 3\r\n" );
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document.write( "    12x - 10x = 3*120\r\n" );
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document.write( "        2x    =  360\r\n" );
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document.write( "         x    =   360/2 = 180.\r\n" );
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document.write( "So, the number of rulers was 180;  the number of erasers was 4x = 4*180 = 720;\r\n" );
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document.write( "    the number of pencils was  =  = 2*5*60 = 600.\r\n" );
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document.write( "Total stationery items was  180 + 720 + 600 = 1500.\r\n" );
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document.write( "(a)  Percentage of erasers to the total stationery was   = 48%.    ANSWER\r\n" );
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document.write( "(b)  The number of rules was 180.    ANSWER\r\n" );
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