document.write( "Question 1199314: How to see that a complete subfield F in Q_p with absolute value | |_p, is actually Q_p itself? \r
\n" ); document.write( "\n" ); document.write( "We have one inclusion: F\subset Q_p.
\n" ); document.write( "Trying to show that Q_p\subset F. Q_p is complete with respect to | |_p. take an element x in F\subset Q_p, so there exists a cauchy sequence x_n in Q_p such that x_n—>x.
\n" ); document.write( "But F id also complete so there exists y_n in F such that
\n" ); document.write( "y_n—>x, but then x_n=y_n, so can we say that Q_p\subset F and we're done?
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Algebra.Com's Answer #848220 by textot(100)\"\" \"About 
You can put this solution on YOUR website!
**1. Key Idea**\r
\n" ); document.write( "\n" ); document.write( "* The crux of the argument lies in the uniqueness of limits in complete metric spaces. \r
\n" ); document.write( "\n" ); document.write( "**2. Proof Outline**\r
\n" ); document.write( "\n" ); document.write( "* **Assume:** We have a complete subfield F of Q_p. This means F is a field itself, and it's complete with respect to the same p-adic absolute value |.|_p as Q_p.\r
\n" ); document.write( "\n" ); document.write( "* **Show Q_p ⊆ F:**
\n" ); document.write( " * Take any x ∈ Q_p.
\n" ); document.write( " * Since Q_p is complete, there exists a Cauchy sequence (x_n) in Q ⊆ F such that x_n → x in Q_p.
\n" ); document.write( " * Since F is a subfield of Q_p, it contains all rational numbers (Q). Therefore, (x_n) is also a Cauchy sequence in F.
\n" ); document.write( " * Since F is complete, this Cauchy sequence (x_n) must converge to a limit y in F.
\n" ); document.write( " * **Uniqueness of Limits:** In any metric space (and hence in Q_p and F), limits are unique. Since x_n → x in Q_p and x_n → y in F, we must have x = y.
\n" ); document.write( " * This shows that for any x ∈ Q_p, there exists a corresponding y ∈ F (namely, y = x).
\n" ); document.write( " * Therefore, Q_p ⊆ F.\r
\n" ); document.write( "\n" ); document.write( "* **Conclusion:**\r
\n" ); document.write( "\n" ); document.write( " * We started with F ⊆ Q_p and proved Q_p ⊆ F.
\n" ); document.write( " * Combining these, we conclude that F = Q_p.\r
\n" ); document.write( "\n" ); document.write( "**In essence:**\r
\n" ); document.write( "\n" ); document.write( "* The completeness of both F and Q_p, along with the uniqueness of limits in complete metric spaces, forces any complete subfield of Q_p to be equal to Q_p itself.\r
\n" ); document.write( "\n" ); document.write( "**Note:** This proof relies heavily on the uniqueness of limits in complete metric spaces. \r
\n" ); document.write( "\n" ); document.write( "Let me know if you have any other questions or would like to explore related concepts!
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