document.write( "Question 1209309: Find all real values of p such that
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Algebra.Com's Answer #848213 by ikleyn(52778) $\"\"$ $\"About$

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document.write( "Expression  2(x+6)(x-p)  represents a parabola opened upward\r\n" );
document.write( "with the vertex  at  x= ,  half-way between x-intercepts -6 and p.\r\n" );
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document.write( "The y-value at the vertex is  \r\n" );
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document.write( "     =  = .\r\n" );
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document.write( "We want\r\n" );
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document.write( "     = -4.\r\n" );
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document.write( "It gives  \r\n" );
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document.write( "     = 8\r\n" );
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document.write( "    6 + p = +/- \r\n" );
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document.write( "    p = -6 +/- .\r\n" );
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document.write( "ANSWER.  There are two real numbers \"p\" satisfying the imposed requirements.\r\n" );
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document.write( "         They are  -6 -   and  -6 + .\r\n" );
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