Algebra.Com's Answer #848204 by ikleyn(52754)  You can put this solution on YOUR website! . \n" );
document.write( "In the sequence 1, 3, 6, 10, 15, 21, ..., in the first 1000 terms of the sequence, \n" );
document.write( "how many terms are multiples of 5? \n" );
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document.write( "The n-th term of this sequence, , is the sum of the first n natural numbers\r\n" );
document.write( " = 1,\r\n" );
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document.write( " = 3 = 1 + 2,\r\n" );
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document.write( " = 6 = 1 + 2 + 3,\r\n" );
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document.write( " = 10 = 1 + 2 + 3 + 4,\r\n" );
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document.write( " = 15 = 1 + 2 + 3 + 4 + 5,\r\n" );
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document.write( "and so on. For the sum of the first natural numbers, there is the formula\r\n" );
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document.write( " = .\r\n" );
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document.write( "So, the question is: how many terms of the first 1000 terms are multiples of 5.\r\n" );
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document.write( "In order for the term be a multiple of 5, EITHER n OR (n+1) must be multiple of 5\r\n" );
document.write( "(here \"either - or\" is exclusive).\r\n" );
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document.write( "Of the first 1000 numbers n = 1, 2, 3, 4, 5, . . . , 1000, there are 1000/5 = 200 multiple of 5.\r\n" );
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document.write( "Of the first 1000 numbers n+1 = 2, 3, 4, 5, . . . , 1001, there are = 200 other numbers multiple of 5.\r\n" );
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document.write( "Thus, in all, among first 1000 numbers = , there are 200 + 200 = 400 numbers multiple of 5.\r\n" );
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document.write( "ANSWER. In the sequence 1, 3, 6, 10, 15, 21, ..., in the first 1000 terms of the sequence, \r\n" );
document.write( " 400 numbers are multiple of 5.\r\n" );
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document.write( "Solved.\r \n" );
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