document.write( "Question 1209306: Let x and y be nonnegative real numbers. If xy = 4/3, then find the minimum value of 2x + 6y + x^2 + 3y^2.
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Algebra.Com's Answer #848182 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Solve \"xy+=+4%2F3\" for y to get \"y+=+4%2F%283x%29\"\r
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\n" ); document.write( "\n" ); document.write( "Then we plug it into the expression to get
\n" ); document.write( "\"2x+%2B+6y+%2B+x%5E2+%2B+3y%5E2\"
\n" ); document.write( "= \"2x+%2B+6%2A%284%2F%283x%29%29+%2B+x%5E2+%2B+3%2A%284%2F%283x%29%29%5E2\"
\n" ); document.write( "= \"%283x%5E4%2B6x%5E3%2B24x%2B16%29%2F%283x%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "The goal is to make \"f%28x%29+=+%283x%5E4%2B6x%5E3%2B24x%2B16%29%2F%283x%5E2%29\" as small as possible.
\n" ); document.write( "Note that x = 0 isn't allowed in the domain so we're focused on the interval x > 0.\r
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\n" ); document.write( "\n" ); document.write( "You can use differential calculus or you can use a graphing calculator to determine the local minimum when x > 0\r
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\n" ); document.write( "\n" ); document.write( "Two recommended graphing tools are Desmos and GeoGebra
\n" ); document.write( "There are many others to pick from.\r
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\n" ); document.write( "\n" ); document.write( "Here's the Desmos graph
\n" ); document.write( "https://www.desmos.com/calculator/nieyc6olhx
\n" ); document.write( "When focusing on the interval x > 0 the lowest part of the red curve is approximately at (1.65132, 12.82996)
\n" ); document.write( "This is marked as the green point on the curve. \r
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\n" ); document.write( "\n" ); document.write( "The y coordinate of this local minimum is the smallest value of \"f%28x%29\" and also the smallest value of the original expression.\r
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\n" ); document.write( "\n" ); document.write( "Side note: be sure not to mix up the y coordinate of the local minimum with the \"y\"s in either xy = 4/3 or 2x + 6y + x^2 + 3y^2. Those are different y values. \r
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\n" ); document.write( "\n" ); document.write( "Answer: 12.82996 (approximate)
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