document.write( "Question 1209306: Let x and y be nonnegative real numbers. If xy = 4/3, then find the minimum value of 2x + 6y + x^2 + 3y^2.
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Algebra.Com's Answer #848182 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Solve \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then we plug it into the expression to get \n" ); document.write( " \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The goal is to make \n" ); document.write( "Note that x = 0 isn't allowed in the domain so we're focused on the interval x > 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can use differential calculus or you can use a graphing calculator to determine the local minimum when x > 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Two recommended graphing tools are Desmos and GeoGebra \n" ); document.write( "There are many others to pick from.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's the Desmos graph \n" ); document.write( "https://www.desmos.com/calculator/nieyc6olhx \n" ); document.write( "When focusing on the interval x > 0 the lowest part of the red curve is approximately at (1.65132, 12.82996) \n" ); document.write( "This is marked as the green point on the curve. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The y coordinate of this local minimum is the smallest value of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side note: be sure not to mix up the y coordinate of the local minimum with the \"y\"s in either xy = 4/3 or 2x + 6y + x^2 + 3y^2. Those are different y values. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 12.82996 (approximate) \n" ); document.write( " \n" ); document.write( " |