document.write( "Question 1205063: You were tasked to program an algorithm for a number generator. The generator will be used by a soda company for their bottlecaps. The soda company will be holding a bottlecap lottery where 5 select bottlecaps will be winning combinations. There would be three characters printed on the bottlecaps with each character having the chance to be repeated. If a second person was to join, how many bottles of Pepsi will the 2nd person need to buy to have a 1% chance at winning. \n" ); document.write( "
Algebra.Com's Answer #848161 by textot(100)![]() ![]() ![]() You can put this solution on YOUR website! **1. Determine the Total Possible Combinations**\r \n" ); document.write( "\n" ); document.write( "* Since there are 3 characters and each character can be repeated, the total number of possible combinations on a bottlecap is 3 * 3 * 3 = 27.\r \n" ); document.write( "\n" ); document.write( "**2. Probability of Winning for the First Person**\r \n" ); document.write( "\n" ); document.write( "* The first person needs to find 5 specific winning combinations out of 27 possible combinations. \n" ); document.write( "* The probability of winning for the first person on any given bottlecap is 5/27.\r \n" ); document.write( "\n" ); document.write( "**3. Probability of Losing for the First Person**\r \n" ); document.write( "\n" ); document.write( "* The probability of losing for the first person on any given bottlecap is 1 - (5/27) = 22/27.\r \n" ); document.write( "\n" ); document.write( "**4. Probability of Losing Consecutively for the Second Person**\r \n" ); document.write( "\n" ); document.write( "* Let 'n' be the number of bottles the second person needs to buy. \n" ); document.write( "* The probability of losing 'n' consecutive times is (22/27)^n.\r \n" ); document.write( "\n" ); document.write( "**5. Determine the Number of Bottles for a 1% Chance of Winning**\r \n" ); document.write( "\n" ); document.write( "* We want the probability of losing consecutively to be 99% (100% - 1%): \n" ); document.write( " * (22/27)^n = 0.99\r \n" ); document.write( "\n" ); document.write( "* Solve for 'n': \n" ); document.write( " * n = log(0.99) / log(22/27) \n" ); document.write( " * n ≈ 0.45 / -0.1823 \n" ); document.write( " * n ≈ 2.47\r \n" ); document.write( "\n" ); document.write( "* Since the second person can't buy a fraction of a bottle, they would need to buy **at least 3 bottles** to have a 1% chance of winning.\r \n" ); document.write( "\n" ); document.write( "**Therefore, the second person needs to buy at least 3 bottles of soda to have a 1% chance of winning.** \n" ); document.write( " \n" ); document.write( " |