document.write( "Question 1209297: Crew a can assemble 2 cars in 5 days, and crew b can assemble 3 cars in 7 days. If both work together assemble 100cars, with crew b working 10 days longer than crew a , how many days must crew be work? \n" ); document.write( "

Algebra.Com's Answer #848119 by ikleyn(52790) $\"\"$ $\"About$

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\n" ); document.write( "Crew A can assemble 2 cars in 5 days, and crew B can assemble 3 cars in 7 days.
\n" ); document.write( "If both work together assemble 100cars, with crew B working 10 days longer than crew A,
\n" ); document.write( "how many days must crew $\"highlight%28cross%28be%29%29\"$ B work?
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document.write( "The setup equation is\r\n" );
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document.write( "     +  +  = 100\r\n" );
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document.write( "Here 2/5 cars per day is the rate of work for team A;\r\n" );
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document.write( "     3/7 cars per day is the rate of work for team B;\r\n" );
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document.write( "     d is the number of days for two teams to work together.\r\n" );
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document.write( "To solve, multiply all the terms by 35.  You will get\r\n" );
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document.write( "    10*3*5 + 2*7*d + 3*5*d = 3500.\r\n" );
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document.write( "Simplify and find \"d\"\r\n" );
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document.write( "    150 + 14d + 15d = 3500\r\n" );
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document.write( "             29d    = 3500 - 150 \r\n" );
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document.write( "             29d    =    3350\r\n" );
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document.write( "               d    =    3350/29 = 115.\r\n" );
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document.write( "ANSWER.  Crew B should work 10 + 115 = 125  days.\r\n" );
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