document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1209284>Question 1209284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> which of the following numbers is the smallest? A. 3/7 B.1/3 C.5/6 D.9/14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #848113 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3817)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=848113\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Answer: <font color=red>1/3</font>\r<BR>\n" );
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document.write( "Explanation\r<BR>\n" );
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document.write( "The other tutors have great responses. <BR>\n" );
document.write( "I'll offer another approach.\r<BR>\n" );
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document.write( "Let's compare the fractions A and B<BR>\n" );
document.write( "For now assume they are equal. <BR>\n" );
document.write( "We can use the cross multiplication rule like so<BR>\n" );
document.write( "3/7 = 1/3<BR>\n" );
document.write( "3*3 = 7*1<BR>\n" );
document.write( "9 = 7<BR>\n" );
document.write( "The last equation is false since the two sides don't agree on the same number.<BR>\n" );
document.write( "To fix the error, change each equal sign to a greater than sign.<BR>\n" );
document.write( "3/7 > 1/3<BR>\n" );
document.write( "3*3 > 7*1<BR>\n" );
document.write( "9 > 7<BR>\n" );
document.write( "We determine that 3/7 is larger than 1/3.<BR>\n" );
document.write( "Cross choice A off the list.<BR>\n" );
document.write( "So far 1/3 is the smallest value. <BR>\n" );
document.write( "But there could be another fraction in this list that's smaller.\r<BR>\n" );
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document.write( "Now let's compare B and C. <BR>\n" );
document.write( "Like before we assume they are equal, and use the cross multiplication rule to get,<BR>\n" );
document.write( "1/3 = 5/6<BR>\n" );
document.write( "1*6 = 3*5<BR>\n" );
document.write( "6 = 15<BR>\n" );
document.write( "This is false, so let's fix the errors.<BR>\n" );
document.write( "1/3 < 5/6<BR>\n" );
document.write( "1*6 < 3*5<BR>\n" );
document.write( "6 < 15<BR>\n" );
document.write( "The fraction 1/3 is still the smallest so far. <BR>\n" );
document.write( "Cross choice C off the list.\r<BR>\n" );
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document.write( "The last comparison is to look at B and D.<BR>\n" );
document.write( "1/3 = 9/14<BR>\n" );
document.write( "1*14 = 3*9<BR>\n" );
document.write( "14 = 27<BR>\n" );
document.write( "Let's fix the errors<BR>\n" );
document.write( "1/3 < 9/14<BR>\n" );
document.write( "1*14 < 3*9<BR>\n" );
document.write( "14 < 27<BR>\n" );
document.write( "Cross choice D off the list since D is larger than B.\r<BR>\n" );
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document.write( "Therefore 1/3 is the smallest fraction in the list.<BR>\n" );
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