document.write( "Question 1200096: The mean height of a population of girls aged 15 to 19 years in a certain population was found to be 165 cm with a standard deviation of 15cm. Assuming that the heights are normally distributed, find the heights in centimeters that correspond to the following percentiles:
\n" ); document.write( "a. Between the 20th and 50th percentiles.
\n" ); document.write( "b. Between the 40th and 60th percentiles.
\n" ); document.write( "c. Between the 10th and 90th percentiles.
\n" ); document.write( "d. Above the 80th percentile.
\n" ); document.write( "e. Below the 10th percentile.
\n" ); document.write( "f. Above the 5th percentile. \r
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Algebra.Com's Answer #848090 by GingerAle(43)\"\" \"About 
You can put this solution on YOUR website!
**1. Find Z-scores:**\r
\n" ); document.write( "\n" ); document.write( "* **Use a Z-table or calculator (like a TI-84) to find the Z-scores corresponding to the given percentiles.**\r
\n" ); document.write( "\n" ); document.write( "**a. Between 20th and 50th percentiles:**
\n" ); document.write( " * Z-score for 20th percentile: -0.84
\n" ); document.write( " * Z-score for 50th percentile: 0 (mean)\r
\n" ); document.write( "\n" ); document.write( "**b. Between 40th and 60th percentiles:**
\n" ); document.write( " * Z-score for 40th percentile: -0.25
\n" ); document.write( " * Z-score for 60th percentile: 0.25\r
\n" ); document.write( "\n" ); document.write( "**c. Between 10th and 90th percentiles:**
\n" ); document.write( " * Z-score for 10th percentile: -1.28
\n" ); document.write( " * Z-score for 90th percentile: 1.28\r
\n" ); document.write( "\n" ); document.write( "**d. Above 80th percentile:**
\n" ); document.write( " * Z-score for 80th percentile: 0.84\r
\n" ); document.write( "\n" ); document.write( "**e. Below 10th percentile:**
\n" ); document.write( " * Z-score for 10th percentile: -1.28\r
\n" ); document.write( "\n" ); document.write( "**f. Above 5th percentile:**
\n" ); document.write( " * Z-score for 5th percentile: -1.645\r
\n" ); document.write( "\n" ); document.write( "**2. Calculate Heights:**\r
\n" ); document.write( "\n" ); document.write( "* **Use the formula: X = μ + Zσ**
\n" ); document.write( " * where X is the height, μ is the mean, Z is the z-score, and σ is the standard deviation.\r
\n" ); document.write( "\n" ); document.write( "**a. Between 20th and 50th percentiles:**
\n" ); document.write( " * 20th percentile: X = 165 + (-0.84)(15) = 151.4 cm
\n" ); document.write( " * 50th percentile: X = 165 + (0)(15) = 165 cm
\n" ); document.write( " * Heights: Between 151.4 cm and 165 cm\r
\n" ); document.write( "\n" ); document.write( "**b. Between 40th and 60th percentiles:**
\n" ); document.write( " * 40th percentile: X = 165 + (-0.25)(15) = 161.25 cm
\n" ); document.write( " * 60th percentile: X = 165 + (0.25)(15) = 168.75 cm
\n" ); document.write( " * Heights: Between 161.25 cm and 168.75 cm\r
\n" ); document.write( "\n" ); document.write( "**c. Between 10th and 90th percentiles:**
\n" ); document.write( " * 10th percentile: X = 165 + (-1.28)(15) = 142.8 cm
\n" ); document.write( " * 90th percentile: X = 165 + (1.28)(15) = 187.2 cm
\n" ); document.write( " * Heights: Between 142.8 cm and 187.2 cm\r
\n" ); document.write( "\n" ); document.write( "**d. Above 80th percentile:**
\n" ); document.write( " * 80th percentile: X = 165 + (0.84)(15) = 177.6 cm
\n" ); document.write( " * Heights: Above 177.6 cm\r
\n" ); document.write( "\n" ); document.write( "**e. Below 10th percentile:**
\n" ); document.write( " * 10th percentile: X = 165 + (-1.28)(15) = 142.8 cm
\n" ); document.write( " * Heights: Below 142.8 cm\r
\n" ); document.write( "\n" ); document.write( "**f. Above 5th percentile:**
\n" ); document.write( " * 5th percentile: X = 165 + (-1.645)(15) = 139.325 cm
\n" ); document.write( " * Heights: Above 139.325 cm \r
\n" ); document.write( "\n" ); document.write( "**Note:** These calculations provide approximate values based on the normal distribution. \r
\n" ); document.write( "\n" ); document.write( "Let me know if you'd like to explore any other percentiles or have further questions!
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