document.write( "Question 1200459: 3. A corporation must appoint a president, chief executive officer (CEO), chief financial officer (CFO) and chief operating officer (COO). It must also appoint a planning committee with six different members. There are 12 qualified candidates, and officers can also serve on the committee.\r
\n" ); document.write( "\n" ); document.write( "(i) How many different ways can the officers be appointed?
\n" ); document.write( "(ii) What is the probability of randomly selecting the officers and getting the youngest candidate a president?
\n" ); document.write( "(iii) How many different ways can the committee be appointed?
\n" ); document.write( "(iv) What is the probability of randomly selecting the committee members and getting the six youngest of the qualified candidates?
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Algebra.Com's Answer #848082 by GingerAle(43)\"\" \"About 
You can put this solution on YOUR website!
Certainly, let's break down the calculations for the corporation's appointments.\r
\n" ); document.write( "\n" ); document.write( "**i) How many different ways can the officers be appointed?**\r
\n" ); document.write( "\n" ); document.write( "* This is a permutation problem since the order of the officers (President, CEO, CFO, COO) matters.
\n" ); document.write( "* We have 12 candidates and need to choose 4 for the officer positions.\r
\n" ); document.write( "\n" ); document.write( "* The formula for permutations is:
\n" ); document.write( " P(n, r) = n! / (n-r)!
\n" ); document.write( " where:
\n" ); document.write( " * n is the total number of items (candidates)
\n" ); document.write( " * r is the number of items to choose (officers)\r
\n" ); document.write( "\n" ); document.write( "* P(12, 4) = 12! / (12-4)! = 12! / 8! = 12 * 11 * 10 * 9 = 11,880\r
\n" ); document.write( "\n" ); document.write( "* **There are 11,880 different ways to appoint the officers.**\r
\n" ); document.write( "\n" ); document.write( "**ii) What is the probability of randomly selecting the officers and getting the youngest candidate a president?**\r
\n" ); document.write( "\n" ); document.write( "* There is only 1 youngest candidate.
\n" ); document.write( "* The probability of selecting the youngest candidate as president is 1 out of the total number of possible presidents (which is the total number of candidates).\r
\n" ); document.write( "\n" ); document.write( "* Probability = 1 / 12 = 0.0833 (approximately)\r
\n" ); document.write( "\n" ); document.write( "* **The probability of randomly selecting the officers and getting the youngest candidate as president is approximately 0.0833 or 8.33%.**\r
\n" ); document.write( "\n" ); document.write( "**iii) How many different ways can the committee be appointed?**\r
\n" ); document.write( "\n" ); document.write( "* This is a combination problem since the order of the committee members does not matter.
\n" ); document.write( "* We have 12 candidates and need to choose 6 for the committee.\r
\n" ); document.write( "\n" ); document.write( "* The formula for combinations is:
\n" ); document.write( " C(n, r) = n! / (r! * (n-r)!)
\n" ); document.write( " where:
\n" ); document.write( " * n is the total number of items (candidates)
\n" ); document.write( " * r is the number of items to choose (committee members)\r
\n" ); document.write( "\n" ); document.write( "* C(12, 6) = 12! / (6! * (12-6)!) = 12! / (6! * 6!) = 924\r
\n" ); document.write( "\n" ); document.write( "* **There are 924 different ways to appoint the committee.**\r
\n" ); document.write( "\n" ); document.write( "**iv) What is the probability of randomly selecting the committee members and getting the six youngest of the qualified candidates?**\r
\n" ); document.write( "\n" ); document.write( "* There is only 1 possible combination of the six youngest candidates.\r
\n" ); document.write( "\n" ); document.write( "* Probability = 1 / 924 = 0.001082 (approximately)\r
\n" ); document.write( "\n" ); document.write( "* **The probability of randomly selecting the committee members and getting the six youngest of the qualified candidates is approximately 0.001082 or 0.1082%.**\r
\n" ); document.write( "\n" ); document.write( "Let me know if you'd like to explore any other scenarios or have further questions!
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