document.write( "Question 1200375: Raffle tickets numbered 1 through 30 are placed in a box. Tickets for a second raffle are
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document.write( "numbered 21 through 48 and placed in a second box. One ticket is randomly drawn from each box.
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document.write( "Find the probability the first ticket is greater than 10, and the second ticket is less than 40 or odd \n" );
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Algebra.Com's Answer #848081 by GingerAle(43)![]() ![]() ![]() You can put this solution on YOUR website! Certainly, let's find the probability.\r \n" ); document.write( "\n" ); document.write( "**1. Probability of the first ticket being greater than 10:**\r \n" ); document.write( "\n" ); document.write( "* There are 20 tickets numbered greater than 10 (from 11 to 30) out of a total of 30 tickets. \n" ); document.write( "* Probability of the first ticket being greater than 10: 20/30 = 2/3\r \n" ); document.write( "\n" ); document.write( "**2. Probability of the second ticket being less than 40 or odd:**\r \n" ); document.write( "\n" ); document.write( "* **Less than 40:** There are 19 tickets less than 40 (from 21 to 39) out of 28 total tickets. \n" ); document.write( "* **Odd numbers:** There are 14 odd numbers (21, 23, 25, ..., 47) out of 28 total tickets. \n" ); document.write( "* **Less than 40 and odd:** There are 10 numbers that are both less than 40 and odd (21, 23, 25, ..., 39).\r \n" ); document.write( "\n" ); document.write( "* To find the probability of \"less than 40 or odd\", we use the formula: \n" ); document.write( " * P(A or B) = P(A) + P(B) - P(A and B) \n" ); document.write( " * where: \n" ); document.write( " * P(A) = Probability of the ticket being less than 40 \n" ); document.write( " * P(B) = Probability of the ticket being odd \n" ); document.write( " * P(A and B) = Probability of the ticket being both less than 40 and odd\r \n" ); document.write( "\n" ); document.write( "* P(less than 40 or odd) = (19/28) + (14/28) - (10/28) = 23/28\r \n" ); document.write( "\n" ); document.write( "**3. Probability of both events happening:**\r \n" ); document.write( "\n" ); document.write( "* Since the draws are independent, the probability of both events happening is the product of their individual probabilities.\r \n" ); document.write( "\n" ); document.write( "* Probability = (Probability of first ticket > 10) * (Probability of second ticket < 40 or odd) \n" ); document.write( "* Probability = (2/3) * (23/28) \n" ); document.write( "* Probability = 23/42\r \n" ); document.write( "\n" ); document.write( "**Therefore, the probability that the first ticket is greater than 10 and the second ticket is less than 40 or odd is 23/42.** \n" ); document.write( " \n" ); document.write( " |